Submission #95886

#	Time	Username	Problem	Language	Result	Execution time	Memory
95886		popovicirobert	Calvinball championship (CEOI15_teams)	C++14	10 / 100	151 ms	580 KiB

teams

#include <bits/stdc++.h>
#define lsb(x) (x & (-x))
#define ll long long
#define ull unsigned long long
#define ld long double
// 217
// 44

using namespace std;

const int MOD = (int) 1e6 + 7;
const int MAXN = 10005;

inline void mod(int &x) {
    if(x >= MOD)
        x -= MOD;
}

int arr[MAXN + 1], mx[MAXN + 1];
int dp[2][MAXN + 1];

int main() {
    //ifstream cin("A.in");
    //ofstream cout("A.out");
    int i, j, n;
    ios::sync_with_stdio(false);
    cin.tie(0), cout.tie(0);
    cin >> n;
    for(i = 1; i <= n; i++) {
        cin >> arr[i];
        mx[i] = max(mx[i - 1], arr[i]);
    }
    for(i = 1; i <= mx[n]; i++) {
        dp[n & 1][i] = i + 1;
    }
    int ans = arr[n] - 1;
    for(i = n - 1; i >= 1; i--) {
        for(j = 1; j <= mx[i]; j++) {
            dp[i & 1][j] = (1LL * dp[1 - i & 1][j] * (j + 1) + dp[1 - i & 1][j + 1]) % MOD;
            //cerr << dp[i & 1][j] << " ";
        }
        //cerr << "\n\n";
        int cur = 0;
        for(j = 1; j < arr[i]; j++) {
            cur += dp[1 - i & 1][mx[i - 1]];
            mod(cur);
        }
        ans += cur;
        mod(ans);
    }
    cout << (ans + 1) % MOD;
    //cin.close();
    //cout.close();
    return 0;
}

Compilation message (stderr)

teams.cpp: In function 'int main()':
teams.cpp:39:40: warning: suggest parentheses around '-' in operand of '&' [-Wparentheses]
             dp[i & 1][j] = (1LL * dp[1 - i & 1][j] * (j + 1) + dp[1 - i & 1][j + 1]) % MOD;
                                      ~~^~~
teams.cpp:39:69: warning: suggest parentheses around '-' in operand of '&' [-Wparentheses]
             dp[i & 1][j] = (1LL * dp[1 - i & 1][j] * (j + 1) + dp[1 - i & 1][j + 1]) % MOD;
                                                                   ~~^~~
teams.cpp:45:25: warning: suggest parentheses around '-' in operand of '&' [-Wparentheses]
             cur += dp[1 - i & 1][mx[i - 1]];
                       ~~^~~

• Subtask 1: 10 / 10
• Subtask 2: 0 / 10
• Subtask 3: 0 / 10
• Subtask 4: 0 / 10
• Subtask 5: 0 / 10
• Subtask 6: 0 / 10
• Subtask 7: 0 / 10
• Subtask 8: 0 / 10
• Subtask 9: 0 / 10
• Subtask 10: 0 / 10