제출 #952476

#제출 시각아이디문제언어결과실행 시간메모리
952476GrindMachineIOI 바이러스 (JOI21_fever)C++17
25 / 100
5014 ms6348 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) (int)a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x,y) ((x+y-1)/(y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i,n) for(int i = 0; i < n; ++i) #define rep1(i,n) for(int i = 1; i <= n; ++i) #define rev(i,s,e) for(int i = s; i >= e; --i) #define trav(i,a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a,b); } template<typename T> void amax(T &a, T b) { a = max(a,b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* refs: https://codeforces.com/blog/entry/88748?#comment-772929 https://oj.uz/submission/802645 (for stress testing) */ const int MOD = 1e9 + 7; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; vector<ll> dx = {1,-1,0,0}; vector<ll> dy = {0,0,1,-1}; void solve(int test_case) { ll n; cin >> n; vector<pll> a(n+5); rep1(i,n) cin >> a[i].ff >> a[i].ss; vector<bool> vis(n+5); ll ans = 0; rep(dir,4){ priority_queue<array<ll,3>, vector<array<ll,3>>, greater<array<ll,3>>> pq; fill(all(vis),0); pq.push({0,1,dir}); while(!pq.empty()){ auto [t,i,d1] = pq.top(); pq.pop(); if(vis[i]) conts; vis[i] = 1; auto [x1,y1] = a[i]; rep1(j,n){ auto [x2,y2] = a[j]; // x1+dx[d1]*k = x2+dx[d2]*k // y1+dy[d1]*k = y2+dy[d2]*k rep(d2,4){ if(dx[d1] == dx[d2] or dy[d1] == dy[d2]) conts; ll k1 = 2*(x2-x1)/(dx[d1]-dx[d2]); ll k2 = 2*(y2-y1)/(dy[d1]-dy[d2]); if(k1 == k2){ if(k1 > t){ array<ll,3> ar = {k1,j,d2}; pq.push(ar); } } } } } ll cnt = count(all(vis),1); amax(ans,cnt); } cout << ans << endl; } int main() { fastio; int t = 1; // cin >> t; rep1(i, t) { solve(i); } return 0; }
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