Submission #940821

#TimeUsernameProblemLanguageResultExecution timeMemory
940821GrindMachineStrange Device (APIO19_strange_device)C++17
100 / 100
378 ms71620 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) (int)a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x,y) ((x+y-1)/(y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i,n) for(int i = 0; i < n; ++i) #define rep1(i,n) for(int i = 1; i <= n; ++i) #define rev(i,s,e) for(int i = s; i >= e; --i) #define trav(i,a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a,b); } template<typename T> void amax(T &a, T b) { a = max(a,b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* read some solutions long time ago, remember some ideas from there */ const int MOD = 1e9 + 7; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; void solve(int test_case) { ll n,A,B; cin >> n >> A >> B; vector<pll> a(n+5); rep1(i,n) cin >> a[i].ff >> a[i].ss; ll g = gcd(A,B+1); ll k = A/g; ll period = 0; if(k > inf2/B){ period = inf2; } else{ period = k*B; } vector<pll> b; rep1(i,n){ auto [l,r] = a[i]; amin(r,l+period-1); l %= period, r %= period; if(l <= r){ b.pb({l,r}); } else{ b.pb({l,period-1}); b.pb({0,r}); } } sort(all(b)); ll mx_reach = -1; ll ans = 0; for(auto [l,r] : b){ if(l > mx_reach){ ans += r-l+1; } else{ ans += max(r-mx_reach,0ll); } amax(mx_reach,r); } cout << ans << endl; } int main() { fastio; int t = 1; // cin >> t; rep1(i, t) { solve(i); } return 0; }
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