제출 #732144

#제출 시각아이디문제언어결과실행 시간메모리
732144GrindMachineCalvinball championship (CEOI15_teams)C++17
70 / 100
1073 ms1712 KiB
// Om Namah Shivaya #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int, int> pii; typedef pair<ll, ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x, y) ((x + y - 1) / (y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i, n) for(int i = 0; i < n; ++i) #define rep1(i, n) for(int i = 1; i <= n; ++i) #define rev(i, s, e) for(int i = s; i >= e; --i) #define trav(i, a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a, b); } template<typename T> void amax(T &a, T b) { a = max(a, b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* */ const int MOD = 1000007; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; void solve(int test_case) { ll n; cin >> n; vector<ll> a(n + 5); rep1(i, n) cin >> a[i]; assert(a[1] == 1); vector<vector<ll>> dp1(n + 5, vector<ll>(2)); dp1[1][1] = 1; for (int i = 2; i <= n; ++i) { vector<vector<ll>> dp2(n + 5, vector<ll>(2)); ll d = a[i]; rep1(j, n + 1) { rep(t, 2) { // < d { ll cnt = min((ll) j, d - 1); dp2[j][0] = (dp2[j][0] + dp1[j][t] * cnt) % MOD; if (j + 1 < d) { dp2[j + 1][0] = (dp2[j + 1][0] + dp1[j][t]) % MOD; } } // = d if (d <= j) { dp2[j][t] = (dp2[j][t] + dp1[j][t]) % MOD; } else if (d == j + 1) { dp2[j + 1][t] = (dp2[j + 1][t] + dp1[j][t]) % MOD; } // > d if (!t) { ll cnt = j - min((ll) j, d); dp2[j][0] = (dp2[j][0] + dp1[j][t] * cnt) % MOD; if (j + 1 > d) { dp2[j + 1][0] = (dp2[j + 1][0] + dp1[j][t]) % MOD; } } } } dp1 = dp2; } ll ans = 0; rep1(j, n + 1) { rep(t, 2) { ans = (ans + dp1[j][t]) % MOD; } } cout << ans << endl; } int main() { fastio; int t = 1; // cin >> t; rep1(i, t) { solve(i); } return 0; }
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