Submission #705509

#	Time	Username	Problem	Language	Result	Execution time	Memory
705509		danikoynov	디지털 회로 (IOI22_circuit)	C++17	4 / 100	3071 ms	11944 KiB

circuit

#include "circuit.h"

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;

const ll mod = 1000002022;
const int maxn = 2e5 + 10;

int n, m, p[maxn], a[maxn];
vector < int > children[maxn];
ll dp[maxn][2], temp[maxn];

void update_state(int v)
{
        dp[v][0] = dp[v][1] = 0;

    if (v >= n)
    {
        dp[v][1] = a[v - n];
        dp[v][0] = 1 - dp[v][1];
        return;
    }

    int c = children[v].size();
    for (int i = 0; i <= c; i ++)
        temp[i] = 0;

    temp[0] = 1;
    for (int u : children[v])
    {
        for (int i = c; i >= 0; i --)
        {
            temp[i] = (temp[i] * dp[u][0]) % mod;
            if (i > 0)
                temp[i] = (temp[i] + temp[i - 1] * dp[u][1]) % mod;
        }
    }


    for (int i = 0; i <= c; i ++)
    {
        dp[v][0] = (dp[v][0] + temp[i] * (ll)(c - i)) % mod;
        dp[v][1] = (dp[v][1] + temp[i] * (ll)(i)) % mod;
    }
    ///cout << v << " " << dp[v][0] << " " << dp[v][1] << endl;

}
void solve_state(int v)
{


    for (int u : children[v])
    {
        solve_state(u);
    }

    update_state(v);



}

ll pw[maxn];
int act = 0, logM = 0;
void init(int N, int M, std::vector<int> P, std::vector<int> A)
{
    n = N;
    m = M;
        pw[0] = 1;
    for (int i = 1; i <= M; i ++)
        pw[i] = (pw[i - 1] * (ll)(2)) % mod;
    while((1 << logM) < M)
        logM ++;
    for (int i = 0; i < N + M; i ++)
        p[i] = P[i];
    for (int i = 0; i < M; i ++)
        a[i] = A[i], act += a[i];

    for (int i = 1; i < N + M; i ++)
    {
        children[p[i]].push_back(i);
    }
    solve_state(0);
}

int tree[4 * maxn], lazy[4 * maxn];


int count_ways(int L, int R)
{
    if (L == R)
    {
        act -= a[L - n];
        a[L - n] = (a[L - n] + 1) % 2;
        act += a[L - n];
        ll ans = (pw[n - logM] * act) % mod;
        return ans;
    }
    else
    {
        for (int i = L - n; i <= R - n; i ++)
            a[i] = ((a[i] + 1) & 1);

        solve_state(0);
    }


    return dp[0][1];
}

• Subtask 1: 0 / 2
• Subtask 2: 0 / 7
• Subtask 3: 0 / 9
• Subtask 4: 4 / 4
• Subtask 5: 0 / 12
• Subtask 6: 0 / 27
• Subtask 7: 0 / 28
• Subtask 8: 0 / 11