제출 #61428

#제출 시각아이디문제언어결과실행 시간메모리
61428qkxwsmXylophone (JOI18_xylophone)C++17
100 / 100
166 ms20944 KiB
#include "xylophone.h"
#include <bits/stdc++.h>

using namespace std;

template<class T>
void readi(T &x)
{
	T input = 0;
	bool negative = false;
	char c = ' ';
	while (c < '-')
	{
		c = getchar();
	}
	if (c == '-')
	{
		negative = true;
		c = getchar();
	}
	while (c >= '0')
	{
		input = input * 10 + (c - '0');
		c = getchar();
	}
	if (negative)
	{
		input = -input;
	}
	x = input;
}
template<class T>
void printi(T output)
{
	if (output == 0)
	{
		putchar('0');
		return;
	}
	if (output < 0)
	{
		putchar('-');
		output = -output;
	}
	int aout[20];
	int ilen = 0;
	while(output)
	{
		aout[ilen] = ((output % 10));
		output /= 10;
		ilen++;
	}
	for (int i = ilen - 1; i >= 0; i--)
	{
		putchar(aout[i] + '0');
	}
	return;
}
template<class T>
void ckmin(T &a, T b)
{
	a = min(a, b);
}
template<class T>
void ckmax(T &a, T b)
{
	a = max(a, b);
}
long long randomize(long long mod)
{
	return ((1ll << 30) * rand() + (1ll << 15) * rand() + rand()) % mod;
}

#define MP make_pair
#define PB push_back
#define PF push_front
#define LB lower_bound
#define UB upper_bound
#define fi first
#define se second

const long double PI = 4.0 * atan(1.0);
const long double EPS = 1e-10;

#define MAGIC 347
#define SINF 10007
#define CO 1000007
#define INF 1000000007
#define BIG 1000000931
#define LARGE 1696969696967ll
#define GIANT 2564008813937411ll
#define LLINF 2696969696969696969ll
#define MAXN 5013

long long normalize(long long x, long long mod = INF)
{
	return (((x % mod) + mod) % mod);
}

typedef long long ll;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;

int N;
int ans[MAXN];
int vis[MAXN][MAXN];

int get(int a, int b)
{
	if (a == b) return 0;
	if (a > b) swap(a, b);
	if (vis[a][b])
	{
		return vis[a][b];
	}
	vis[a][b] = query(a + 1, b + 1);
	return vis[a][b];
}

void solve(int n)
{
	N = n;
	ans[0] = 0;
	ans[1] = get(0, 1);
	for (int i = 2; i < N; i++)
	{
		int x = get(i - 2, i), y = get(i - 1, i);
		int u = ans[i - 1] + y, d = ans[i - 1] - y;
		int big = max(u, max(ans[i - 1], ans[i - 2]));
		int small = min(u, min(ans[i - 1], ans[i - 2]));
		if (big - small == x)
		{
			ans[i] = u;
		}
		else
		{
			ans[i] = d;
		}
	}
	int sm = INF;
	for (int i = 0; i < N; i++)
	{
		ckmin(sm, ans[i]);
	}
	for (int i = 0; i < N; i++)
	{
		ans[i] -= sm;
	}
	bool flag = false;
	for (int i = 0; i < N; i++)
	{
		if (ans[i] == 0)
		{
			break;
		}
		if (ans[i] == N - 1)
		{
			flag = true;
			break;
		}
	}
	if (flag)
	{
		for (int i = 0; i < N; i++)
		{
			ans[i] = (N - 1) - ans[i];
		}
	}
//	cerr << lo << ' ' << hi << endl;
	for (int i = 0; i < N; i++)
	{
		answer(i + 1, ans[i] + 1);
	}
}
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