이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
/**
____ ____ ____ ____ ____ ____
||l |||e |||i |||n |||a |||d ||
||__|||__|||__|||__|||__|||__||
|/__\|/__\|/__\|/__\|/__\|/__\|
**/
#include<bits/stdc++.h>
#define endl '\n'
using namespace std;
typedef long long ll;
void speed()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
}
const int maxn = 3e5 + 10;
int n;
ll k, a[maxn], dp[maxn][2], cnt[maxn][2], par[maxn];
pair < ll, int > calc(ll cost)
{
dp[0][1] = -1e18;
for (int i = 1; i <= n; i ++)
{
dp[i][0] = max(dp[i - 1][0], dp[i - 1][1]);
dp[i][1] = max(dp[i - 1][0] - cost, dp[i - 1][1]) + a[i];
cnt[i][1] = cnt[i][0] = 0;
if (dp[i - 1][0] == dp[i][0])
cnt[i][0] = max(cnt[i][0], cnt[i - 1][0]);
if (dp[i - 1][1] == dp[i][0])
cnt[i][0] = max(cnt[i][0], cnt[i - 1][1]);
if (dp[i - 1][0] - cost + a[i] == dp[i][1])
cnt[i][1] = max(cnt[i][1], cnt[i - 1][0] + 1);
if (dp[i - 1][1] + a[i] == dp[i][1])
cnt[i][1] = max(cnt[i][1], cnt[i - 1][1]);
}
//for (int i = 1; i <= n; i ++)
// cout << dp[i][0] << " - " << dp[i][1] << endl;
pair < ll, int > ans = {dp[1][0], cnt[1][0]};
for (int i = 1; i <= n; i ++)
for (int j = 0; j < 2; j ++)
if (make_pair((ll)dp[i][j], (int)cnt[i][j]) > ans)
ans = {dp[i][j], cnt[i][j]};
return ans;
/**for (int i = 1; i <= n; i ++)
{
dp[i] = dp[i - 1];
cnt[i] = cnt[i - 1];
for (int j = 1; j <= i; j ++)
{
ll sum = dp[j - 1] - cost + par[i] - par[j - 1];
if (sum > dp[i])
dp[i] = sum;
if (sum == dp[i])
cnt[i] = max(cnt[i], cnt[j - 1] + 1);
}
}
pair < ll, int > ans = {dp[1], cnt[1]};
for (int i = 2; i <= n; i ++)
if (make_pair((ll)dp[i], (int)cnt[i]) > ans)
ans = {dp[i], cnt[i]};
return ans;*/
}
void solve()
{
cin >> n >> k;
ll cnt = 0, neg = 0;
for (int i = 1; i <= n; i ++)
{
cin >> a[i];
if (a[i] >= 0)
cnt ++;
else
neg ++;
par[i] = par[i - 1] + a[i];
}
k = min(cnt, k);
if (neg == 1)
{
ll f1 = 0, f2 = 0, pos = -1;
for (int i = 1; i <= n; i ++)
{
if (a[i] < 0)
{
pos = i;
break;
}
f1 += a[i];
}
for (int i = n; i > 0; i --)
{
if (a[i] < 0)
{
pos = i;
break;
}
f2 += a[i];
}
if (pos == -1)
{
cout << f1 << endl;
}
else
{
if (k == 2)
cout << f1 + f2 << endl;
else
cout << max(f1, max(f2, f1 + f2 + a[pos]));
}
return;
}
ll lf = 0, rf = 1e12;
while(lf <= rf)
{
ll mf = (lf + rf) / 2;
pair < double, int > cur = calc(mf);
if (cur.second >= k)
lf = mf + 1;
else
rf = mf - 1;
}
double p1 = lf - 1, p2 = lf;
pair < ll, int > cur1 = calc(p1), cur2 = calc(p2);
cur1.first = cur1.first + cur1.second * p1;
cur2.first = cur2.first + cur2.second * p2;
double part = 1.0 - (double)(cur1.second - k) / (double)(cur1.second - cur2.second);
double slope = (cur1.first - cur2.first);
double ans = cur2.first + slope * part;
///cout << cur1.second << " " << cur2.second << " " << part << " " << cur1.second - k << " " << k << endl;
if (cur1.second == cur2.second)
{
cout << cur1.first << endl;
return;
}
cout << (ll)round(ans) << endl;
}
int main()
{
solve();
return 0;
}
/**
7 1
3 4 -1 2 3 -5 1
*/
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