oj.uz

답안 #571358

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
571358 2022-06-01T22:43:57 Z PedroBigMan 사탕 분배 (IOI21_candies) C++17
100 / 100
 3133 ms 491572 KB 
#include "candies.h"
#include <bits/stdc++.h>
 
using namespace std;
using ll = long long;
const int BS = 333;
 
 
vector<ll> compute_function(const vector<int>& ops) {
  vector<ll> stk;
  stk.push_back(4e18);
  stk.push_back(2e18);
  for (auto delta : ops) {
    if (delta == 0) continue;
    if (delta > 0) {
      ll rem = delta, px = 0;
      while (true) {
        ll x = stk.back();
        if (x - px > rem) {
          stk.push_back(px + rem);
          stk.push_back(0);
          break;
        } 
        rem -= (x - px);
        stk.pop_back();
        px = stk.back();
        stk.pop_back();
      }
    } else {
      ll rem = -delta;
      while (true) {
        ll px = stk.back(); stk.pop_back();
        ll x = stk.back();
        if (x - px > rem) {
          stk.push_back(px + rem);
          break;
        }
        rem -= (x - px);
        stk.pop_back();
      }
    }
  }
  
  stk.push_back(0);
  stk.push_back(0);
  reverse(stk.begin(), stk.end());
  return stk;
}
 
vector<int> distribute_candies(
    vector<int> c, vector<int> l,
    vector<int> r, vector<int> v) {
  int n = c.size();
 
  
  // Sort each bucket increasingly by c[i] to facilitate easy evaluation of f.
  vector<int> order(n);
  iota(order.begin(), order.end(), 0);
  for (int i = 0; i < n; i += BS) {
    int j = min(i + BS, n);
    sort(order.begin() + i, order.begin() + j, [&](int a, int b) {
      return c[a] < c[b];
    });
  }
 
  vector<ll> stk;
  vector<int> a(n, 0), na(n, 0);
  vector<vector<int>> ops(n / BS + 1);
 
  auto commit = [&](int bi) {
    if (ops[bi].empty()) return;
    int l = bi * BS, r = min(n, (bi + 1) * BS);
 
    // compute f(.) and evaluate it in all c[i] of this bucket
    auto stk = compute_function(ops[bi]);
    ll value = 0;
    int ptr = 0;
    for (int i = l; i < r; ++i) {
      int ci = c[order[i]];
      while (stk[ptr + 1] < ci) {
        if (ptr % 2 == 0)
          value += stk[ptr + 1] - stk[ptr];
        ++ptr;
      }
      if (ptr % 2 == 0) {
        na[order[i]] = value + (ci - stk[ptr]);
      } else {
        na[order[i]] = value;
      }
    }
  
    // Adapt for non-zero initial values.
    ll mind = 0, maxd = 0, nowd = 0;
    for (auto x : ops[bi]) {
      nowd += x;
      mind = min(mind, nowd);
      maxd = max(maxd, nowd);
    }
    for (int i = l; i < r; ++i) {
      ll hi = min(c[i] - maxd, (ll)a[i]);
      ll lo = -mind;
      if (lo < hi) 
        na[i] += hi - lo; 
    }
 
    // Housekeeping.
    for (int i = l; i < r; ++i) 
      a[i] = na[i];
    ops[bi].clear();
  };
 
  int q = l.size();
  for (int i = 0; i < q; ++i) {
    int bl = l[i] / BS, br = r[i] / BS;
    commit(bl); commit(br); 
    for (int j = l[i]; j <= r[i]; ) {
      if (j % BS == 0 && (j + BS - 1) <= r[i]) {
        ops[j / BS].push_back(v[i]);
        j += BS;
      } else {
        a[j] = max(0, min(a[j] + v[i], c[j]));
        j += 1;
      }
    }
  }
 
  for (int i = 0; i < n; i += BS)
    commit(i / BS);
  return a;
}

Subtask #1
3.0 / 3.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 212 KB Output is correct
2 Correct 1 ms 212 KB Output is correct
3 Correct 1 ms 312 KB Output is correct
4 Correct 1 ms 468 KB Output is correct
5 Correct 7 ms 340 KB Output is correct

Subtask #2
8.0 / 8.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1855 ms 12864 KB Output is correct
2 Correct 2013 ms 12632 KB Output is correct
3 Correct 1926 ms 12764 KB Output is correct

Subtask #3
27.0 / 27.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 212 KB Output is correct
2 Correct 499 ms 6084 KB Output is correct
3 Correct 67 ms 6304 KB Output is correct
4 Correct 1647 ms 12816 KB Output is correct
5 Correct 1662 ms 12788 KB Output is correct
6 Correct 1578 ms 13072 KB Output is correct
7 Correct 1462 ms 12756 KB Output is correct

Subtask #4
29.0 / 29.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 1 ms 212 KB Output is correct
3 Correct 486 ms 10536 KB Output is correct
4 Correct 71 ms 10060 KB Output is correct
5 Correct 3133 ms 491308 KB Output is correct
6 Correct 2907 ms 491572 KB Output is correct
7 Correct 2923 ms 491456 KB Output is correct
8 Correct 2907 ms 491416 KB Output is correct
9 Correct 2250 ms 491476 KB Output is correct

Subtask #5
33.0 / 33.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 212 KB Output is correct
2 Correct 1 ms 212 KB Output is correct
3 Correct 1 ms 312 KB Output is correct
4 Correct 1 ms 468 KB Output is correct
5 Correct 7 ms 340 KB Output is correct
6 Correct 1855 ms 12864 KB Output is correct
7 Correct 2013 ms 12632 KB Output is correct
8 Correct 1926 ms 12764 KB Output is correct
9 Correct 1 ms 212 KB Output is correct
10 Correct 499 ms 6084 KB Output is correct
11 Correct 67 ms 6304 KB Output is correct
12 Correct 1647 ms 12816 KB Output is correct
13 Correct 1662 ms 12788 KB Output is correct
14 Correct 1578 ms 13072 KB Output is correct
15 Correct 1462 ms 12756 KB Output is correct
16 Correct 0 ms 212 KB Output is correct
17 Correct 1 ms 212 KB Output is correct
18 Correct 486 ms 10536 KB Output is correct
19 Correct 71 ms 10060 KB Output is correct
20 Correct 3133 ms 491308 KB Output is correct
21 Correct 2907 ms 491572 KB Output is correct
22 Correct 2923 ms 491456 KB Output is correct
23 Correct 2907 ms 491416 KB Output is correct
24 Correct 2250 ms 491476 KB Output is correct
25 Correct 1 ms 212 KB Output is correct
26 Correct 71 ms 6440 KB Output is correct
27 Correct 530 ms 7640 KB Output is correct
28 Correct 2129 ms 16464 KB Output is correct
29 Correct 2062 ms 16728 KB Output is correct
30 Correct 1894 ms 17128 KB Output is correct
31 Correct 1755 ms 17136 KB Output is correct
32 Correct 1634 ms 17356 KB Output is correct