제출 #49195

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
49195		tmwilliamlin168	호화 벙커 (IZhO13_burrow)	C++14	100 / 100	535 ms	4604 KiB

burrow

#include <bits/stdc++.h>
using namespace std;

#define getchar_unlocked getchar
#define putchar_unlocked putchar

inline int in() {
	int result = 0;
	char ch = getchar_unlocked();
	while (true) {
		if(ch >= '0' && ch <= '9')
			break;
		ch = getchar_unlocked();
	}
	result = ch-'0';
	while(true) {
		ch = getchar_unlocked();
		if (ch < '0' || ch > '9')
			break;
		result = result*10 + (ch - '0');
	}
	return result;
}
inline void out(int x) {
	int rev=x, count = 0;
	while((rev % 10) == 0) {
++count;
rev /= 10;
} //obtain the count of the number of 0s
	rev = 0;
	while(x != 0) {
rev = rev*10 + x % 10;
x /= 10;
} //store reverse of N in rev
	while(rev != 0) {
putchar_unlocked(rev % 10 + '0');
rev /= 10;
}
	while(count--)
putchar_unlocked('0');
}

const int mxN=1000;
int n, m, k, a[mxN][mxN], lb=1, rb=1e9, mb, a2, a3, b[2][mxN], l[mxN], r[mxN];

int main() {
	n=in(), m=in(), k=in();
	for(int i=0; i<n; ++i)
		for(int j=0; j<m; ++j)
			a[i][j]=in();
	while(lb<=rb) {
		mb=(lb+rb)/2, a3=0;
		memset(b[n&1], 0, 4*m);
		for(int i=n-1; i>=0; --i) {
			for(int j=0; j<m; ++j)
				b[i&1][j]=a[i][j]<mb?0:b[i&1^1][j]+1;
			for(int j=0; j<m; ++j) {
				l[j]=j-1;
				while(l[j]>=0&&b[i&1][l[j]]>=b[i&1][j])
					l[j]=l[l[j]];
			}
			for(int j=m-1; j>=0; --j) {
				r[j]=j+1;
				while(r[j]<m&&b[i&1][r[j]]>=b[i&1][j])
					r[j]=r[r[j]];
				a3=max(b[i&1][j]*(r[j]-l[j]-1), a3);
			}
		}
		if(a3>=k) {
			lb=mb+1;
			a2=a3;
		} else
			rb=mb-1;
	}
	out(rb);
	putchar_unlocked(' ');
	out(a2);
}

컴파일 시 표준 에러 (stderr) 메시지

burrow.cpp: In function 'int main()':
burrow.cpp:56:31: warning: suggest parentheses around arithmetic in operand of '^' [-Wparentheses]
     b[i&1][j]=a[i][j]<mb?0:b[i&1^1][j]+1;
                              ~^~

• Subtask 1: 100 / 100