Submission #478380

#TimeUsernameProblemLanguageResultExecution timeMemory
478380blueVision Program (IOI19_vision)C++17
21 / 100
124 ms2852 KiB
#include "vision.h" #include <vector> using namespace std; int checkifleq(int H, int W, int K_) //check if one diagonal is equal to K { int K = K_; vector<int> diag_res; for(int V = 1; V <= 2; V++) { vector<int> diag1_list; if(V == 1) { for(int d1 = 0; d1 <= H-1 + W-1; d1++) { vector<int> op; for(int i = 0; i < H; i++) { for(int j = 0; j < W; j++) { if(i+j == d1) op.push_back(W*i + j); } } diag1_list.push_back(add_or(op)); } } else { for(int d1 = 0-(W-1); d1 <= (H-1)-0; d1++) { vector<int> op; for(int i = 0; i < H; i++) { for(int j = 0; j < W; j++) { if(i-j == d1) op.push_back(W*i + j); } } diag1_list.push_back(add_or(op)); } } vector<int> diag1_comp_list; for(int i = 0; i+K < (int)diag1_list.size(); i++) { diag1_comp_list.push_back(add_and(vector<int>{diag1_list[i], diag1_list[i+K]})); } diag_res.push_back(add_or(diag1_comp_list)); } return add_or(diag_res); } void construct_network(int H, int W, int K) { int Kexists = checkifleq(H, W, K); vector<int> gK{Kexists}; for(int k = K+1; k <= H+W-2; k++) { gK.push_back(add_not(checkifleq(H, W, k))); } add_and(gK); }
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