이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
ll INF = 1e9+7;
ll MOD = 998244353;
typedef pair<ll,ll> ii;
#define iii pair<ll,ii>
#define f(i,a,b) for(ll i = a;i < b;i++)
#define pb push_back
#define vll vector<ll>
#define F first
#define S second
#define all(x) (x).begin(), (x).end()
///I hope I will get uprating and don't make mistakes
///I will never stop programming
///sqrt(-1) Love C++
///Please don't hack me
///@TheofanisOrfanou Theo830
///Think different approaches (bs,dp,greedy,graphs,shortest paths,mst)
///Stay Calm
///Look for special cases
///Beware of overflow and array bounds
///Think the problem backwards
///Deltix Round, Spring 2021 (open for everyone, rated, Div. 1 + Div. 2)
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
uniform_int_distribution<ll> distr;
ll rnd(ll a, ll b){return distr(rng)%(b-a+1)+a;}
/*
#define inbuf_len 1 << 16
#define outbuf_len 1 << 16
int GetBestPosition(int N, int C, int R, int *K, int *S, int *E);
int main() {
int tmp;
char *inbuf, *outbuf;
inbuf = (char*) malloc(inbuf_len * sizeof(char));
outbuf = (char*) malloc(outbuf_len * sizeof(char));
tmp = setvbuf(stdin, inbuf, _IOFBF, inbuf_len);
assert(tmp == 0);
tmp = setvbuf(stdout, outbuf, _IOFBF, outbuf_len);
assert(tmp == 0);
int N, C, R;
int *K, *S, *E;
tmp = scanf("%d %d %d", &N, &C, &R);
assert(tmp == 3);
K = (int*) malloc((N-1) * sizeof(int));
S = (int*) malloc(C * sizeof(int));
E = (int*) malloc(C * sizeof(int));
int i;
for (i = 0; i < N-1; i++) {
tmp = scanf("%d", &K[i]);
assert(tmp == 1);
}
for (i = 0; i < C; i++) {
tmp = scanf("%d %d", &S[i], &E[i]);
assert(tmp == 2);
}
printf("%d\n", GetBestPosition(N, C, R, K, S, E));
return 0;
}
*/
int GetBestPosition(int N, int C, int R, int *K, int *S, int *E) {
ll posa = 0;
ll ans = 0;
vll arr;
f(i,0,N){
ll res = 0;
arr.clear();
f(j,0,N-1){
if(j == i){
arr.pb(R);
}
arr.pb(K[j]);
}
if(i == N-1){
arr.pb(R);
}
f(j,0,C){
ll maxi = 0;
f(k,S[j],E[j]+1){
maxi = max(maxi,arr[k]);
}
vll neo;
bool ok = 0;
f(k,0,S[j]){
neo.pb(arr[k]);
}
neo.pb(maxi);
ok |= maxi == R;
f(k,E[j]+1,N){
neo.pb(arr[k]);
}
arr = neo;
res += ok;
}
if(res > posa){
posa = res;
ans = i;
}
}
return ans;
}
/*
5 3 3
1
0
2
4
1 3
0 1
0 1
*/
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