이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "encoder.h"
#include "encoderlib.h"
#include <bits/stdc++.h>
using namespace std;
const int H = 320 + 256 + 3;
const int SZ = 90;
struct Big_Number{
int a[SZ];
void init(){ fill(a, a + SZ, 0); }
Big_Number(){ init(); }
friend Big_Number operator+(const Big_Number &l, const Big_Number &r){
int add = 0;
Big_Number ret;
for(int i = SZ - 1; i >= 0; --i){
int sum = l.a[i] + r.a[i] + add;
ret.a[i] = sum % 256;
add = sum / 256;
}
return ret;
}
friend bool operator<(const Big_Number &l, const Big_Number &r){
for(int i = 0; i < SZ; ++i)
if(l.a[i] != r.a[i])
return l.a[i] < r.a[i];
return false;
}
};
static bool done = false;
static Big_Number bc[H][H];
static void output_number(Big_Number bn){
bool start = false;
for(int i = 0; i < SZ; ++i){
if(bn.a[i]) start = true;
if(start) cout << bn.a[i] << " ";
}
cout << endl;
}
void encode(int n, int m[]){
if(!done){
bc[0][0].a[SZ - 1] = 1;
for(int i = 0; i < H; ++i){
bc[i][0].a[SZ - 1] = 1;
for(int j = 1; j <= i; ++j)
bc[i][j] = bc[i - 1][j] + bc[i - 1][j - 1];
}
done = true;
}
int t = 5 * n, num = 255;
Big_Number curr, add;
for(int i = 0; i < n; ++i)
curr.a[SZ - 1 - i] = m[i];
for(; t > 0; --t){
while(num && curr < bc[t + num - 1][t] + add) num--;
send(num);
add = add + bc[t + num - 1][t];
}
}
#include "decoder.h"
#include "decoderlib.h"
#include <bits/stdc++.h>
using namespace std;
const int H = 320 + 256 + 3;
const int SZ = 90;
struct Big_Number{
int a[SZ];
void init(){ fill(a, a + SZ, 0); }
Big_Number(){ init(); }
friend Big_Number operator+(const Big_Number &l, const Big_Number &r){
int add = 0;
Big_Number ret;
for(int i = SZ - 1; i >= 0; --i){
int sum = l.a[i] + r.a[i] + add;
ret.a[i] = sum % 256;
add = sum / 256;
}
return ret;
}
friend bool operator<(const Big_Number &l, const Big_Number &r){
for(int i = 0; i < SZ; ++i)
if(l.a[i] != r.a[i])
return l.a[i] < r.a[i];
return false;
}
};
static bool done = false;
static Big_Number bc[H][H];
void decode(int n, int l, int x[]){
if(!done){
bc[0][0].a[SZ - 1] = 1;
for(int i = 0; i < H; ++i){
bc[i][0].a[SZ - 1] = 1;
for(int j = 1; j <= i; ++j)
bc[i][j] = bc[i - 1][j] + bc[i - 1][j - 1];
}
done = true;
}
sort(x, x + l);
int t = 5 * n, num = 255;
Big_Number curr;
for(; t > 0; --t){
int num = x[t - 1];
curr = curr + bc[t + num - 1][t];
}
for(int i = 0; i < n; ++i)
output(curr.a[SZ - 1 - i]);
}
컴파일 시 표준 에러 (stderr) 메시지
encoder.cpp:38:13: warning: 'void output_number(Big_Number)' defined but not used [-Wunused-function]
38 | static void output_number(Big_Number bn){
| ^~~~~~~~~~~~~
decoder.cpp: In function 'void decode(int, int, int*)':
decoder.cpp:51:20: warning: unused variable 'num' [-Wunused-variable]
51 | int t = 5 * n, num = 255;
| ^~~
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