Submission #339911

#	Time	Username	Problem	Language	Result	Execution time	Memory
339911		blue	자동 인형 (IOI18_doll)	C++11	9 / 100	89 ms	8484 KiB

doll

#include "doll.h"
#include <vector>
#include <iostream>
using namespace std;

void create_circuit(int M, vector<int> A)
{
    vector<int> C(M+1, -1);
    vector<int> X, Y;
    int N = A.size();

    C[0] = A[0];

    if(N == 1)
    {
        C = vector<int>(M+1, 0);
        answer(C, X, Y);
        return;
    }

    int p;

    for(p = 1; 2*(1 << p) < N; p++); //1<<p is the size of the last row of the binary tree (1<<p) <= N < (1<<p+1)
    X = vector<int>( (1 << (p+1)) - 1 , -1);
    Y = vector<int>( (1 << (p+1)) - 1 , -1);

    for(int i = 2; i <= (1 << (p+1)) - 1; i++)
    {
        if(i % 2 == 0) X[i/2 - 1] = -i;
        else Y[i/2 - 1] = -i;
    }

    // cout << "0 " << C[0] << '\n';
    // for(int i = 1; i < (1 << (p+1)); i++) cout << i << ' ' << X[i-1] << ' ' << Y[i-1] << '\n';

    for(int i = (1 << (p+1)); i < (1 << (p+2)); i++)
    {
        // cout << "switch = " << i << '\n';
        if(i - (1 << (p+1)) + 1 < N)
        {
            if(i % 2 == 0) X[i/2 - 1] = A[i - (1 << (p+1)) + 1];
            else Y[i/2 - 1] = A[i - (1 << (p+1)) + 1];
        }
        else if(i == (1 << (p+2))-1)
        {
            Y[i/2 - 1] = 0;
        }
        else
        {
            if(i % 2 == 0) X[i/2 - 1] = -1;
            else Y[i/2 - 1] = -1;
        }
    }

    answer(C, X, Y);
}

• Subtask 1: 0 / 2
• Subtask 2: 0 / 4
• Subtask 3: 0 / 10
• Subtask 4: 0 / 10
• Subtask 5: 9.0000000036 / 18
• Subtask 6: 0 / 56