이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "split.h"
#include <bits/stdc++.h>
using namespace std;
typedef vector<int> vi;
typedef pair<int,int> ii;
static vi answer;
static vi adj[100005];
static vi child[100005];
static vi tree[100005];
static int sz[100005];
static int p[100005];
static bool vis[100005];
void dfs(int u){
vis[u] = true;
sz[u] = 1;
for(int v : adj[u]){
if(!vis[v]){
child[u].push_back(v);
tree[u].push_back(v);
tree[v].push_back(u);
p[v] = u;
dfs(v);
sz[u] += sz[v];
}
}
}
void bfs(int root, int number){
if(number == 0) return;
queue<int> bf;
bf.push(root);
while(!bf.empty()){
int u = bf.front(); bf.pop();
for(int v : adj[u]){
if(answer[v] == 0){
answer[v] = answer[u];
number--;
if(number == 0) return;
bf.push(v);
}
}
}
}
vi find_split(int n, int aaa, int bbb, int ccc, vi p, vi q) {
vector<ii> v = {ii(aaa,1),ii(bbb,2),ii(ccc,3)};
sort(v.begin(),v.end());
int A = v[0].first;
int B = v[1].first;
int AColour = v[0].second;
int BColour = v[1].second;
int CColour = v[2].second;
answer.assign(n,0);
for(int i = 0;i < (int) p.size();i++){
int x = p[i], y = q[i];
adj[y].push_back(x);
adj[x].push_back(y);
}
dfs(0);
for(int u = 0;u < n;u++){
vector<ii> subtrees;
for(int v : child[u]){
subtrees.push_back({sz[v],v});
}
subtrees.push_back({n - sz[u],p[u]});
for(ii x : subtrees){
if(x.first >= A && n - x.first >= B){
//cout << x.second << " " << u << "\n";
answer[x.second] = AColour;
answer[u] = BColour;
bfs(x.second, A-1);
bfs(u,B-1);
for(int i = 0;i < n;i++){
if(answer[i] == 0) answer[i] = CColour;
}
return answer;
}
}
}
return answer;
}
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