답안 #1073383

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
1073383 2024-08-24T13:50:54 Z GrindMachine 사탕 분배 (IOI21_candies) C++17
0 / 100
5000 ms 52736 KB
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

using namespace std;
using namespace __gnu_pbds;

template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
typedef long long int ll;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;

#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL)
#define pb push_back
#define endl '\n'
#define sz(a) a.size()
#define setbits(x) __builtin_popcountll(x)
#define ff first
#define ss second
#define conts continue
#define ceil2(x, y) ((x + y - 1) / (y))
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define yes cout << "Yes" << endl
#define no cout << "No" << endl

#define rep(i, n) for(int i = 0; i < n; ++i)
#define rep1(i, n) for(int i = 1; i <= n; ++i)
#define rev(i, s, e) for(int i = s; i >= e; --i)
#define trav(i, a) for(auto &i : a)

template<typename T>
void amin(T &a, T b) {
    a = min(a, b);
}

template<typename T>
void amax(T &a, T b) {
    a = max(a, b);
}

#ifdef LOCAL
#include "debug.h"
#else
#define debug(x) 42
#endif

/*

refs:
https://codeforces.com/blog/entry/92083?#comment-807860

*/

const int MOD = 1e9 + 7;
const int N = 1e5 + 5;
const int inf1 = int(1e9) + 5;
const ll inf2 = ll(1e18) + 5;

#include "candies.h"

template<typename T>
struct lazysegtree {
    /*=======================================================*/

    struct data {
        ll mn,mnp,mx,mxp;
    };

    struct lazy {
        ll a;
    };

    data d_neutral = {inf2,-1,-inf2,-1};
    lazy l_neutral = {0};

    void merge(data &curr, data &left, data &right) {
        curr.mn = min(left.mn,right.mn);
        curr.mx = max(left.mx,right.mx);
        if(left.mn < right.mn) curr.mnp = left.mnp;
        else curr.mnp = right.mnp;
        if(left.mx > right.mx) curr.mxp = left.mxp;
        else curr.mxp = right.mxp;
    }

    void create(int x, int lx, int rx, T v) {
        tr[x].mn = tr[x].mx = 0;
        tr[x].mnp = tr[x].mxp = lx;
    }

    void modify(int x, int lx, int rx, T v) {
        lz[x].a = v;
    }

    void propagate(int x, int lx, int rx) {
        ll v = lz[x].a;
        if(!v) return;

        tr[x].mn += v, tr[x].mx += v;

        if(rx-lx > 1){
            lz[2*x+1].a += v;
            lz[2*x+2].a += v;
        }

        lz[x] = l_neutral;
    }

    /*=======================================================*/

    int siz = 1;
    vector<data> tr;
    vector<lazy> lz;

    lazysegtree() {

    }

    lazysegtree(int n) {
        while (siz < n) siz *= 2;
        tr.assign(2 * siz, d_neutral);
        lz.assign(2 * siz, l_neutral);
    }

    void build(int n, int x, int lx, int rx) {
        if (rx - lx == 1) {
            if (lx < n) {
                create(x, lx, rx, 0);
            }

            return;
        }

        int mid = (lx + rx) / 2;

        build(n, 2 * x + 1, lx, mid);
        build(n, 2 * x + 2, mid, rx);

        merge(tr[x], tr[2 * x + 1], tr[2 * x + 2]);
    }

    void build(int n) {
        build(n, 0, 0, siz);
    }

    void rupd(int l, int r, T v, int x, int lx, int rx) {
        propagate(x, lx, rx);

        if (lx >= r or rx <= l) return;
        if (lx >= l and rx <= r) {
            modify(x, lx, rx, v);
            propagate(x, lx, rx);
            return;
        }

        int mid = (lx + rx) / 2;

        rupd(l, r, v, 2 * x + 1, lx, mid);
        rupd(l, r, v, 2 * x + 2, mid, rx);

        merge(tr[x], tr[2 * x + 1], tr[2 * x + 2]);
    }

    void rupd(int l, int r, T v) {
        rupd(l, r + 1, v, 0, 0, siz);
    }

    data query(int l, int r, int x, int lx, int rx) {
        propagate(x, lx, rx);

        if (lx >= r or rx <= l) return d_neutral;
        if (lx >= l and rx <= r) return tr[x];

        int mid = (lx + rx) / 2;

        data curr;
        data left = query(l, r, 2 * x + 1, lx, mid);
        data right = query(l, r, 2 * x + 2, mid, rx);

        merge(curr, left, right);
        return curr;
    }

    data query(int l, int r) {
        return query(l, r + 1, 0, 0, siz);
    }
};

std::vector<int> distribute_candies(std::vector<int> b, std::vector<int> L,
                                    std::vector<int> R, std::vector<int> V) {
    ll n = sz(b), q = sz(L);
    vector<pll> enter[n+5], leave[n+5];

    rep(i,q){
        ll l = L[i], r = R[i], v = V[i];
        enter[l].pb({v,i+2});
        leave[r+1].pb({v,i+2});
    }

    enter[0].pb({inf2,0});
    enter[0].pb({-inf2,1});
    lazysegtree<ll> st(q+5);
    st.build(q+2);
    
    vector<int> ans(n);

    rep(i,n){
        for(auto [v,id] : enter[i]){
            st.rupd(id,q+1,v);
        }
        for(auto [v,id] : leave[i]){
            st.rupd(id,q+1,-v);
        }

        ll l = 0, r = q+1;
        ll upper = -1;

        while(l <= r){
            ll mid = (l+r) >> 1;
            auto [mn,mnp,mx,mxp] = st.query(mid,q+1);
            if(mx-st.query(mxp+1,q+1).mn <= b[i]){
                upper = mid;
                r = mid-1;
            }
            else{
                l = mid+1;
            }
        }

        l = 0, r = q+1;
        ll lower = -1;

        while(l <= r){
            ll mid = (l+r) >> 1;
            auto [mn,mnp,mx,mxp] = st.query(mid,q+1);
            if(st.query(mnp+1,q+1).mx-mn <= b[i]){
                lower = mid;
                r = mid-1;
            }
            else{
                l = mid+1;
            }
        }

        ll pos = min(upper,lower);
        auto [suffmn,mnp,suffmx,mxp] = st.query(pos+1,q+1);
        ll lower_wall = -1;

        if(st.query(pos,pos).mn > suffmx){
            // pos = upper wall touch
            lower_wall = suffmn;
        }
        else{
            // pos = lower wall touch
            lower_wall = suffmx-b[i];
        }

        ans[i] = st.query(q+1,q+1).mn-lower_wall;
    }

    return ans;
}
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 348 KB Output is correct
2 Incorrect 1 ms 348 KB Output isn't correct
3 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 4957 ms 52736 KB Output is correct
2 Execution timed out 5094 ms 51792 KB Time limit exceeded
3 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 344 KB Output is correct
2 Incorrect 371 ms 39520 KB Output isn't correct
3 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 344 KB Output is correct
2 Incorrect 1 ms 348 KB Output isn't correct
3 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 348 KB Output is correct
2 Incorrect 1 ms 348 KB Output isn't correct
3 Halted 0 ms 0 KB -