이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <iostream>
#include <vector>
#include "doll.h"
using namespace std;
int l[1000000],r[1000000],num[25],d[1000000];
void create_circuit(int M, std::vector<int> A) {
int n = A.size();
int t=1,p=0;
while(t<n)
{
t*=2;
p++;
}
if(t==n)
{
t*=2;
p++;
}
std::vector<int> C(M + 1);
C[0] = -1;
for (int i = 1; i <= M; ++i) {
C[i] = 1;
}
std::vector<int> X(t-1), Y(t-1);
for (int k = 0; k < n; ++k) {
X[k] = Y[k] = A[k];
}
num[1]=-1;
for(int i=1;i<=t+1;i++)
{
num[1]++;
for(int j=1;j<=p+1;j++)
{
if(num[j]==2)
{
num[j]=0;
num[j+1]++;
}
else break;
}
int q=1;
for(int j=p;j>=1;j--)
{
d[i]+=q*num[j];
q*=2;
}
}
for(int i=1;i<=t-1;i++)
{
l[i]=(i*2)*-1;
r[i]=(i*2+1)*-1;
if(i*2>t-1)l[i]=-1;
if(i*2+1>t-1)r[i]=-1;
}
//for(int i=1;i<=t-1;i++)cout<<l[i]<<" ";
//cout<<endl;
//for(int i=1;i<=t-1;i++)cout<<r[i]<<" ";
//cout<<endl;
for(int i=1;i<=n;i++)
{
if(d[i]%2==1)r[(t+d[i])/2]=A[i-1];
else l[(t+d[i])/2]=A[i-1];
//cout<<d[i]%2<<" "<<(t+d[i])/2<<endl;
}
//for(int i=t/2;i<=t-1;i++)cout<<l[i]<<" "<<r[i]<<" ";
//cout<<endl;
C[0]=-1;
for(int i=1;i<=M;i++)C[i]=-1;
if(n==t)C[A[n-1]]=0;
else r[t-1]=0;
//cout<<endl;
for(int i=0;i<t-1;i++)X[i]=l[i+1];
//cout<<endl;
for(int i=0;i<t-1;i++)Y[i]=r[i+1];
//for(int i=0;i<t-1;i++)cout<<X[i]<<" ";
//cout<<endl;
//for(int i=0;i<t-1;i++)cout<<Y[i]<<" ";
//cout<<endl;
answer(C, X, Y);
}
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