제출 #992020

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
992020		LOLOLO	Poklon (COCI17_poklon)	C++17	0 / 140	267 ms	46160 KiB

poklon

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
 
#define           f     first
#define           s     second
#define           pb    push_back
#define           ep    emplace
#define           eb    emplace_back
#define           lb    lower_bound
#define           ub    upper_bound
#define       all(x)    x.begin(), x.end()
#define      rall(x)    x.rbegin(), x.rend()
#define   uniquev(v)    sort(all(v)), (v).resize(unique(all(v)) - (v).begin())
#define     mem(f,x)    memset(f , x , sizeof(f))
#define        sz(x)    (ll)(x).size()
#define  __lcm(a, b)    (1ll * ((a) / __gcd((a), (b))) * (b))
#define          mxx    *max_element
#define          mnn    *min_element
#define    cntbit(x)    __builtin_popcountll(x)
#define       len(x)    (int)(x.length())

const int N = 5e5 + 100;
int a[N];
vector <int> pos[N];
vector < pair <int, int>> ask[N];
int f[N], ans[N];

void upd(int i, int x) {
    for (; i; i -= i & (-i))
        f[i] += x;
}

int get(int i) {
    int s = 0;
    for (; i < N; i += i & (-i))
        s += f[i];

    return s;
}

int main() {
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);

    int timer = 1;

    int n, q;
    cin >> n >> q;

    map <int, int> mp;

    for (int i = 1; i <= n; i++) {
        cin >> a[i];
        mp[a[i]];
    }

    for (auto &x : mp) {
        x.s = timer;
        timer++;
    }

    for (int i = 1; i <= q; i++) {
        int l, r;
        cin >> l >> r;
        ask[r].pb({l, i});
    }

    for (int i = 1; i <= n; i++) {
        a[i] = mp[a[i]];
    }

    for (int i = 1; i <= n; i++) {
        int ss = sz(pos[a[i]]);
        if (ss) {
            upd(pos[a[i]].back(), 1);
        }

        if (ss > 1) { 
            upd(pos[a[i]][ss - 2], -2);
        }

        pos[a[i]].pb(i);
        for (auto x : ask[i]) {
            ans[x.s] = get(x.f);
        }
    }

    for (int i = 1; i <= q; i++)
        cout << ans[i] << '\n';

    return 0;
}  

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