Submission #981620

#	Time	Username	Problem	Language	Result	Execution time	Memory
981620		8pete8	서열 (APIO23_sequence)	C++17	28 / 100	217 ms	12100 KiB

sequence

#include "sequence.h"
#include<iostream>
#include<stack>
#include<map>
#include<vector>
#include<string>
#include<unordered_map>
#include <queue>
#include<cstring>
#include<limits.h>
#include <cassert>
#include<cmath>
#include<set>
#include<algorithm>
#include <iomanip>
#include<numeric> //gcd(a,b)
#include<bitset>
#include <cstdlib> 
#include <cstdint>
using namespace std;
#define ll long long
#define f first
//#define endl "\n"
#define s second
#define pii pair<int,int>
#define ppii pair<int,pii>
#define vi vector<int>
#define pb push_back
#define all(x) x.begin(),x.end()
#define rall(x) x.rbegin(),x.rend()
#define F(n) for(int i=0;i<n;i++)
#define lb lower_bound
#define ub upper_bound
#define fastio ios::sync_with_stdio(false);cin.tie(NULL);
#pragma GCC optimize ("03,unroll-loops")
#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
using namespace std;
const int mxn=5e5,lg=24,inf=1e18,minf=-1e18;
int mx=0;
struct fen{
  //using fenwick cus i dont wanna write slding median
  int fwk[mxn+10];
  vector<pii>keep;
  void update(int pos,int val){
    keep.pb({pos,val});
    for(int i=pos;i<=mx;i+=(i&-i))fwk[i]+=val;
  }
  int qry(int pos){
    if(pos<0)return 0;
    int sum=0;
    for(int i=pos;i>0;i-=(i&-i))sum+=fwk[i];
    return sum;
  }
  void re(){
    for(auto i:keep)for(int j=i.f;j<=mx;j+=(j&-j))fwk[j]-=i.s;
    keep.clear();
  }
  int get(int x){
    x++;
    int pos=0,sum=0;
    for(int i=lg;i>=0;i--){
      if(pos+(1LL<<i)<=mx&&fwk[pos+(1LL<<i)]+sum<x){
        pos+=(1LL<<i);
        sum+=fwk[pos];
      }
    }
    return pos+1;
  }
}t;
int cnt[mxn+10],r[mxn+10];
int sequence(int n, vector<int>v){
  int ans=0;
  if(n>2e3){
    //sub 3 case get l,r or get l-> other side
    for(auto i:v)cnt[i]++;
    for(int i=0;i<n;i++)r[v[i]]=max(r[v[i]],i);
    for(int i=0;i<n;i++){
      int cur=i;
      while(cur<v.size()&&v[cur]==v[i])cur++;
      ans=max(ans,cur-i);//take range l,r
      
      //or we take here -> the other side
      int other=n-(r[v[i]]-i+1);//number of number <i
      //we can only do it if we can make the median <=x
      if(other+cnt[v[i]]<=(n/2)+1)ans=max(ans,cnt[v[i]]);
      i=cur-1;
    }
    return ans;
  }
  for(auto i:v)mx=max(mx,i);
  auto bru=[&](int x){
    int a=t.get(x);
    return t.qry(a)-t.qry(a-1);
  };
  for(int i=0;i<n;i++){
    t.re();
    for(int j=i;j<n;j++){
      t.update(v[j],1);
      int x1=(j-i)/2,x2=ceil((j-i)*1.0/2*1.0);
      ans=max({ans,bru(x1),bru(x2)});
    }
  }
  if(ans==0)assert(0);
  return ans;
}
/*
int32_t main(){
  int n;cin>>n;
  vector<int>v(n);
  for(int i=0;i<n;i++)cin>>v[i];
  cout<<sequence(n,v);
}*/
/*
7
1 2 3 1 2 1 3
*/

/*
constraint of being a medain
A number of number <x,B number of number >x,C number of number ==x
if C>=A+B
if A+C>=B && C<=A+B
if A+B>=c && B<=A+C
i might be wrong
*/

Compilation message (stderr)

sequence.cpp:38:29: warning: overflow in conversion from 'double' to 'int' changes value from '1.0e+18' to '2147483647' [-Woverflow]
   38 | const int mxn=5e5,lg=24,inf=1e18,minf=-1e18;
      |                             ^~~~
sequence.cpp:38:39: warning: overflow in conversion from 'double' to 'int' changes value from '-1.0e+18' to '-2147483648' [-Woverflow]
   38 | const int mxn=5e5,lg=24,inf=1e18,minf=-1e18;
      |                                       ^~~~~
sequence.cpp: In function 'int sequence(int, std::vector<int>)':
sequence.cpp:79:16: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
   79 |       while(cur<v.size()&&v[cur]==v[i])cur++;
      |             ~~~^~~~~~~~~

• Subtask 1: 11 / 11
• Subtask 2: 17 / 17
• Subtask 3: 0 / 7
• Subtask 4: 0 / 12
• Subtask 5: 0 / 13
• Subtask 6: 0 / 22
• Subtask 7: 0 / 18