제출 #976073

#제출 시각아이디문제언어결과실행 시간메모리
9760738pete8철인 이종 경기 (APIO18_duathlon)C++17
100 / 100
83 ms34896 KiB
#include<iostream> #include<stack> #include<map> #include<vector> #include<string> #include<unordered_map> #include <queue> #include<cstring> #include<limits.h> #include <cassert> #include<cmath> #include<set> #include<algorithm> #include <iomanip> #include<numeric> //gcd(a,b) #include<bitset> #include <cstdlib> #include <cstdint> using namespace std; #define ll long long #define f first //#define endl "\n" #define s second #define pii pair<int,int> #define ppii pair<int,pii> #define vi vector<int> #define pb push_back #define all(x) x.begin(),x.end() #define rall(x) x.rbegin(),x.rend() #define F(n) for(int i=0;i<n;i++) #define lb lower_bound #define ub upper_bound #define fastio ios::sync_with_stdio(false);cin.tie(NULL); #pragma GCC optimize ("03,unroll-loops") #pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt") using namespace std; #define int long long #define double long double const int mxn=2e5,inf=1e18,minf=-1e18; vector<int>adj[mxn+10],adj2[mxn+10]; int tin[mxn+10],low[mxn+10],T=0,on[mxn+10],cnt=0,id[mxn+10],sz[mxn+10]; stack<int>st; int ans=0,n,m,par,forest[mxn+10],idcnt=0; vector<int>comp[mxn+10]; void tarjan(int cur,int p){ tin[cur]=low[cur]=++T; st.push(cur); for(auto i:adj[cur]){ if(i==p)continue; if(tin[i])low[cur]=min(low[cur],tin[i]); else{ tarjan(i,cur); low[cur]=min(low[cur],low[i]); if(low[i]>=tin[cur]){ adj2[cur].pb(++idcnt); while(adj2[idcnt].empty()||adj2[idcnt].back()!=i)adj2[idcnt].pb(st.top()),st.pop(); } } } } int subsz[mxn+10]; void dfs(int cur,int p){ subsz[cur]=(cur<=n); forest[cur]=par; for(auto i:adj2[cur])if(i!=p){ dfs(i,cur); subsz[cur]+=subsz[i]; } } int32_t main(){ fastio cin>>n>>m; for(int i=0;i<m;i++){ int a,b;cin>>a>>b; adj[a].pb(b); adj[b].pb(a); } idcnt=n; for(int i=1;i<=n;i++)if(!tin[i]){ tarjan(i,0); par=i; dfs(i,0); ans+=(subsz[i])*(subsz[i]-1)*(subsz[i]-2); } int x; for(int i=n+1;i<=idcnt;i++){ /* choose any 2 diff node in the subtree j because i is block (all adjacent node are cut node) so (a,node,b) is not possible */ for(auto j:adj2[i]){ x=subsz[j]; ans-=(x)*(x-1)*(adj2[i].size()); } x=subsz[forest[i]]-subsz[i]; ans-=(x)*(x-1)*(adj2[i].size()); } cout<<ans; return 0; }
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