이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
typedef long long int ll;
typedef long double ld;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL)
#define pb push_back
#define endl '\n'
#define sz(a) (int)a.size()
#define setbits(x) __builtin_popcountll(x)
#define ff first
#define ss second
#define conts continue
#define ceil2(x,y) ((x+y-1)/(y))
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define yes cout << "Yes" << endl
#define no cout << "No" << endl
#define rep(i,n) for(int i = 0; i < n; ++i)
#define rep1(i,n) for(int i = 1; i <= n; ++i)
#define rev(i,s,e) for(int i = s; i >= e; --i)
#define trav(i,a) for(auto &i : a)
template<typename T>
void amin(T &a, T b) {
a = min(a,b);
}
template<typename T>
void amax(T &a, T b) {
a = max(a,b);
}
#ifdef LOCAL
#include "debug.h"
#else
#define debug(x) 42
#endif
/*
knew beforehand that this problem could be solved with segtree
*/
int MOD = 1e9 + 7;
const int N = 1e5 + 5;
const int inf1 = int(1e9) + 5;
const ll inf2 = ll(1e18) + 5;
void solve(int test_case)
{
ll n,m; cin >> n >> m >> MOD;
vector<pll> a(n+5);
rep1(i,n) cin >> a[i].ff >> a[i].ss;
sort(a.begin()+1,a.begin()+n+1);
vector<ll> cnt(m+5);
rep1(i,n) cnt[a[i].ss]++;
vector<ll> mnl(m+5,inf2);
rep1(i,n) amin(mnl[a[i].ss],a[i].ff);
vector<bool> came(m+5);
bool bad[m+5][m+5];
memset(bad,0,sizeof bad);
ll ptr = n;
ll ans = 0;
rev(i,n,1){
auto [len,x] = a[i];
while(ptr >= 1 and a[ptr].ff > len/2){
cnt[a[ptr].ss]--;
ptr--;
}
if(came[x]) conts;
came[x] = 1;
ll prod = 1;
rep1(y,m){
if(bad[x][y]) conts;
if(y != x and mnl[y] <= len/2){
bad[y][x] = 1;
}
if(y != x){
if(mnl[y] <= len/2){
prod = prod*(cnt[y]+1)%MOD;
}
}
else{
prod = prod*(cnt[y]+1)%MOD;
}
}
ans = (ans+prod)%MOD;
}
cout << ans << endl;
}
int main()
{
fastio;
int t = 1;
// cin >> t;
rep1(i, t) {
solve(i);
}
return 0;
}
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