Submission #970373

#TimeUsernameProblemLanguageResultExecution timeMemory
970373GrindMachine장난감 기차 (IOI17_train)C++17
11 / 100
1683 ms50708 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) (int)a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x,y) ((x+y-1)/(y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i,n) for(int i = 0; i < n; ++i) #define rep1(i,n) for(int i = 1; i <= n; ++i) #define rev(i,s,e) for(int i = s; i >= e; --i) #define trav(i,a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a,b); } template<typename T> void amax(T &a, T b) { a = max(a,b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* */ const int MOD = 1e9 + 7; const int N = 5e3 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; #include "train.h" vector<int> adj[N]; bool edge[N][N]; bool path[N][N]; vector<bool> vis(N); void dfs1(int u, int r){ vis[u] = 1; path[r][u] = 1; trav(v,adj[u]){ if(vis[v]) conts; dfs1(v,r); } } vector<bool> in_cyc(N); vector<bool> good(N); void dfs2(int u, int r){ vis[u] = 1; trav(v,adj[u]){ if(!good[v]) conts; if(vis[v]){ if(v == r){ in_cyc[r] = 1; } } else{ dfs2(v,r); } } } std::vector<int> who_wins(std::vector<int> a, std::vector<int> b, std::vector<int> U, std::vector<int> V) { int n = sz(a); int m = sz(U); rep(i,m){ int u = U[i], v = V[i]; adj[u].pb(v); edge[u][v] = 1; } vector<int> ans(n,1); rep(i,n){ fill(all(vis),0); dfs1(i,i); } rep(i,n) good[i] = b[i]^1; rep(i,n){ if(!good[i]) conts; fill(all(vis),0); dfs2(i,i); } rep(i,n){ rep(j,n){ if(path[i][j] and !b[j] and in_cyc[j]){ ans[i] = 0; } } } return ans; }
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