제출 #969674

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
969674		LOLOLO	자매 도시 (APIO20_swap)	C++17	7 / 100	583 ms	524288 KiB

swap

#include <bits/stdc++.h>
#include "swap.h"
#define ll long long
using namespace std;
 
#define           f     first
#define           s     second
#define           pb    push_back
#define           ep    emplace
#define           eb    emplace_back
#define           lb    lower_bound
#define           ub    upper_bound
#define       all(x)    x.begin(), x.end()
#define      rall(x)    x.rbegin(), x.rend()
#define   uniquev(v)    sort(all(v)), (v).resize(unique(all(v)) - (v).begin())
#define     mem(f,x)    memset(f , x , sizeof(f))
#define        sz(x)    (int)(x).size()
#define  __lcm(a, b)    (1ll * ((a) / __gcd((a), (b))) * (b))
#define          mxx    *max_element
#define          mnn    *min_element
#define    cntbit(x)    __builtin_popcountll(x)
#define       len(x)    (int)(x.length())
 
const int N = 3e5 + 50;
int a[N];

struct dsu{
    vector <int> sz, par, line, cost, st, en, degree;
    vector < vector <int>> in, p, cc;
    vector < vector <pair <int, int>>> ed;
    int dfstimer = 1;

    void prepare(int n) {
        sz.assign(n + 1, 1);
        par.assign(n + 1, 0);
        line.assign(n + 1, 1);
        cost.assign(n + 1, 1e9 + 10);
        st.assign(n + 1, 0);
        en.assign(n + 1, 0);
        degree.assign(n + 1, 0);
        in.resize(n + 1);
        ed.resize(n + 1);

        for (int i = 0; i <= n; i++) {
            in[i].pb(i);
            p.pb(vector <int> (20, 0));
            cc.pb(vector <int> (20, 0));
        }
    }

    int get(int a) {
        return par[a] ? get(par[a]) : a;
    }

    void dfs(int u, int v) {
        st[u] = ++dfstimer;
        p[u][0] = v;
        for (int j = 1; j < 20; j++) {
            p[u][j] = p[p[u][j - 1]][j - 1];
            cc[u][j] = max(cc[u][j - 1], cc[p[u][j - 1]][j - 1]);
        }

        for (auto x : ed[u]) {
            if (x.f == v)
                continue;

            cc[x.f][0] = x.s;
            dfs(x.f, u);
        }

        en[u] = dfstimer;
    }

    bool is(int a, int b) {
        return st[a] <= st[b] && en[a] >= st[b];
    }

    int lca(int a, int b) {
        if (is(a, b))
            return a;

        if (is(b, a))
            return b;

        for (int j = 19; j >= 0; j--) {
            if (is(p[a][j], b) == 0)
                a = p[a][j];
        }

        return p[a][0];
    }

    int answer(int a, int b) {
        int c = lca(a, b), ans = max(cost[a], cost[b]);
        for (int j = 19; j >= 0; j--) {
            if (p[a][j] != c && is(c, p[a][j])) {
                ans = max(ans, cc[a][j]);
                a = p[a][j];
            }

            if (p[b][j] != c && is(c, p[b][j])) {
                ans = max(ans, cc[b][j]);
                b = p[b][j];
            }
        }

        return ans;
    }

    void unite(int a, int b, int w) {
        int x = a, y = b;
        degree[a]++;
        degree[b]++;
        int mx = max(degree[a], degree[b]);

        a = get(a), b = get(b);
        if (a == b) {
            line[a] = 0;
            for (auto x : in[a]) {
                cost[x] = w;
            }

            in[a].clear();
            return;
        }

        ed[x].pb({y, w});
        ed[y].pb({x, w});
        if (sz[a] < sz[b])
            swap(a, b);

        par[b] = a;
        line[a] = line[a] & line[b];
        if (mx > 2) {
            line[a] = 0; 
        }

        for (auto x : in[b])
            in[a].pb(x);

        if (line[a] == 0) {
            for (auto x : in[a]) {
                cost[x] = w;
            }
            in[a].clear();
        }
    }
} D;

void init(int n, int m, vector <int> u, vector <int> v, vector <int> w) {
    dsu D1;
    D = D1;
    D.prepare(n);
    vector < vector <int>> edge;
    for (int i = 0; i < m; i++) {
        edge.pb({w[i], u[i] + 1, v[i] + 1});
    }

    sort(all(edge));
    for (auto x : edge) {
        D.unite(x[1], x[2], x[0]);
    }

    D.dfs(1, 1);
}

int getMinimumFuelCapacity(int a, int b) {
    a++;
    b++;
    int ans = D.answer(a, b);
    if (ans > 1e9)
        return -1;

    return ans;
}

/*
==================================================+
INPUT:                                            |
--------------------------------------------------|
5 6
0 1 4
0 2 4
1 2 1
1 3 2
1 4 10
2 3 3
3
1 2
2 4
0 1
--------------------------------------------------|
3 2
0 1 5
0 2 5
1
1 2
--------------------------------------------------|
==================================================+
OUTPUT:                                           |
--------------------------------------------------|
3

10
4
--------------------------------------------------|
-1
--------------------------------------------------|
==================================================+
*/

• Subtask 1: 0 / 6
• Subtask 2: 7 / 7
• Subtask 3: 0 / 17
• Subtask 4: 0 / 20
• Subtask 5: 0 / 23
• Subtask 6: 0 / 27