Submission #963945

#TimeUsernameProblemLanguageResultExecution timeMemory
963945GrindMachineReconstruction Project (JOI22_reconstruction)C++17
0 / 100
5103 ms766104 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) (int)a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x,y) ((x+y-1)/(y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i,n) for(int i = 0; i < n; ++i) #define rep1(i,n) for(int i = 1; i <= n; ++i) #define rev(i,s,e) for(int i = s; i >= e; --i) #define trav(i,a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a,b); } template<typename T> void amax(T &a, T b) { a = max(a,b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* refs: some solutions */ const int MOD = 1e9 + 7; const int N = 500 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; vector<pll> adj[N]; vector<ll> active; ll mn_on_path; void dfs1(ll u, ll p, ll des, ll mn){ if(u == des){ mn_on_path = mn; } for(auto [v,id] : adj[u]){ if(v == p) conts; dfs1(v,u,des,min(mn,id)); } } void solve(int test_case) { ll n,m; cin >> n >> m; vector<array<ll,3>> edges(m+5); rep1(i,m){ ll u,v,w; cin >> u >> v >> w; edges[i] = {w,u,v}; } sort(edges.begin()+1,edges.begin()+m+1); vector<vector<ll>> possible; rep1(i,m){ mn_on_path = inf2; auto [w,u,v] = edges[i]; dfs1(u,-1,v,inf2); if(mn_on_path != inf2){ auto [w,x,y] = edges[mn_on_path]; active.erase(find(all(active),mn_on_path)); pll px = {x,mn_on_path}, py = {y,mn_on_path}; adj[x].erase(find(all(adj[x]),py)); adj[y].erase(find(all(adj[y]),px)); } active.pb(i); adj[u].pb({v,i}), adj[v].pb({u,i}); if(sz(active) == n-1){ possible.pb(active); } } rep1(i,n){ adj[i].clear(); } active.clear(); rev(i,m,1){ mn_on_path = inf2; auto [w,u,v] = edges[i]; dfs1(u,-1,v,inf2); if(mn_on_path != inf2){ mn_on_path = -mn_on_path; auto [w,x,y] = edges[mn_on_path]; active.erase(find(all(active),mn_on_path)); pll px = {x,-mn_on_path}, py = {y,-mn_on_path}; adj[x].erase(find(all(adj[x]),py)); adj[y].erase(find(all(adj[y]),px)); } active.pb(i); adj[u].pb({v,-i}), adj[v].pb({u,-i}); if(sz(active) == n-1){ possible.pb(active); } } ll q; cin >> q; while(q--){ ll x; cin >> x; ll ans = inf2; trav(v,possible){ ll cost = 0; trav(id,v){ cost += abs(edges[id][0]-x); } amin(ans,cost); } cout << ans << endl; } } int main() { fastio; int t = 1; // cin >> t; rep1(i, t) { solve(i); } return 0; }
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