제출 #960462

#제출 시각아이디문제언어결과실행 시간메모리
960462GrindMachine섬 항해 (CEOI13_adriatic)C++17
100 / 100
192 ms202664 KiB
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

using namespace std;
using namespace __gnu_pbds;

template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
typedef long long int ll;
typedef long double ld;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;

#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL)
#define pb push_back
#define endl '\n'
#define sz(a) (int)a.size()
#define setbits(x) __builtin_popcountll(x)
#define ff first
#define ss second
#define conts continue
#define ceil2(x,y) ((x+y-1)/(y))
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define yes cout << "Yes" << endl
#define no cout << "No" << endl

#define rep(i,n) for(int i = 0; i < n; ++i)
#define rep1(i,n) for(int i = 1; i <= n; ++i)
#define rev(i,s,e) for(int i = s; i >= e; --i)
#define trav(i,a) for(auto &i : a)

template<typename T>
void amin(T &a, T b) {
    a = min(a,b);
}

template<typename T>
void amax(T &a, T b) {
    a = max(a,b);
}

#ifdef LOCAL
#include "debug.h"
#else
#define debug(x) 42
#endif

/*

refs:
edi

*/

const int MOD = 1e9 + 7;
const int N = 2500 + 5;
const int inf1 = int(1e9) + 5;
const ll inf2 = ll(1e18) + 5;

int here[N][N], p[N][N], mni[N][N], mxi[N][N], mnj[N][N], mxj[N][N], dp1[N][N], dp2[N][N];

void solve(int test_case)
{
    int n; cin >> n;
    vector<pii> a(n+5);
    rep1(i,n) cin >> a[i].ff >> a[i].ss;

    memset(mni,0x3f,sizeof mni);
    memset(mnj,0x3f,sizeof mnj);
    memset(mxi,-0x3f,sizeof mxi);
    memset(mxj,-0x3f,sizeof mxj);

    rep1(i,n) here[a[i].ff][a[i].ss] = 1;

    rep1(i,N-2){
        rep1(j,N-2){
            p[i][j] = p[i-1][j]+p[i][j-1]-p[i-1][j-1]+here[i][j];
        }
    }

    rep1(i,N-2){
        rep1(j,N-2){
            mni[i][j] = min(mni[i-1][j],mni[i][j-1]);
            mnj[i][j] = min(mnj[i-1][j],mnj[i][j-1]);
            if(here[i][j]){
                amin(mni[i][j],i);
                amin(mnj[i][j],j);
            }
        }
    }

    rev(i,N-2,1){
        rev(j,N-2,1){
            mxi[i][j] = max(mxi[i+1][j],mxi[i][j+1]);
            mxj[i][j] = max(mxj[i+1][j],mxj[i][j+1]);
            if(here[i][j]){
                amax(mxi[i][j],i);
                amax(mxj[i][j],j);
            }
        }
    }

    auto f = [&](int r1, int r2, int c1, int c2){
        return p[r2][c2]-p[r1-1][c2]-p[r2][c1-1]+p[r1-1][c1-1];
    };

    // top-right rect
    rep1(i,N-2){
        rev(j,N-2,1){
            dp1[i][j] = f(1,i,j,N-2);
            if(!dp1[i][j]) conts;
            int r = mni[i][j-1], c = mxj[i+1][j];
            amin(r,i);
            amax(c,j);
            if(r >= 1 and r <= N-2 and c >= 1 and c <= N-2){
                dp1[i][j] += dp1[r][c];
            }
        }
    }

    // bottom-left rect
    rev(i,N-2,1){
        rep1(j,N-2){
            dp2[i][j] = f(i,N-2,1,j);
            int r = mxi[i][j+1], c = mnj[i-1][j];
            amax(r,i);
            amin(c,j);
            if(r >= 1 and r <= N-2 and c >= 1 and c <= N-2){
                dp2[i][j] += dp2[r][c];
            }
        }
    }

    rep1(i,n){
        auto [r,c] = a[i];
        int ans = n-1+dp1[r][c]-1+dp2[r][c]-1;
        cout << ans << endl;
    }
}

int main()
{
    fastio;

    int t = 1;
    // cin >> t;

    rep1(i, t) {
        solve(i);
    }

    return 0;
}
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