제출 #960462

#제출 시각아이디문제언어결과실행 시간메모리
960462GrindMachine섬 항해 (CEOI13_adriatic)C++17
100 / 100
192 ms202664 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) (int)a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x,y) ((x+y-1)/(y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i,n) for(int i = 0; i < n; ++i) #define rep1(i,n) for(int i = 1; i <= n; ++i) #define rev(i,s,e) for(int i = s; i >= e; --i) #define trav(i,a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a,b); } template<typename T> void amax(T &a, T b) { a = max(a,b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* refs: edi */ const int MOD = 1e9 + 7; const int N = 2500 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; int here[N][N], p[N][N], mni[N][N], mxi[N][N], mnj[N][N], mxj[N][N], dp1[N][N], dp2[N][N]; void solve(int test_case) { int n; cin >> n; vector<pii> a(n+5); rep1(i,n) cin >> a[i].ff >> a[i].ss; memset(mni,0x3f,sizeof mni); memset(mnj,0x3f,sizeof mnj); memset(mxi,-0x3f,sizeof mxi); memset(mxj,-0x3f,sizeof mxj); rep1(i,n) here[a[i].ff][a[i].ss] = 1; rep1(i,N-2){ rep1(j,N-2){ p[i][j] = p[i-1][j]+p[i][j-1]-p[i-1][j-1]+here[i][j]; } } rep1(i,N-2){ rep1(j,N-2){ mni[i][j] = min(mni[i-1][j],mni[i][j-1]); mnj[i][j] = min(mnj[i-1][j],mnj[i][j-1]); if(here[i][j]){ amin(mni[i][j],i); amin(mnj[i][j],j); } } } rev(i,N-2,1){ rev(j,N-2,1){ mxi[i][j] = max(mxi[i+1][j],mxi[i][j+1]); mxj[i][j] = max(mxj[i+1][j],mxj[i][j+1]); if(here[i][j]){ amax(mxi[i][j],i); amax(mxj[i][j],j); } } } auto f = [&](int r1, int r2, int c1, int c2){ return p[r2][c2]-p[r1-1][c2]-p[r2][c1-1]+p[r1-1][c1-1]; }; // top-right rect rep1(i,N-2){ rev(j,N-2,1){ dp1[i][j] = f(1,i,j,N-2); if(!dp1[i][j]) conts; int r = mni[i][j-1], c = mxj[i+1][j]; amin(r,i); amax(c,j); if(r >= 1 and r <= N-2 and c >= 1 and c <= N-2){ dp1[i][j] += dp1[r][c]; } } } // bottom-left rect rev(i,N-2,1){ rep1(j,N-2){ dp2[i][j] = f(i,N-2,1,j); int r = mxi[i][j+1], c = mnj[i-1][j]; amax(r,i); amin(c,j); if(r >= 1 and r <= N-2 and c >= 1 and c <= N-2){ dp2[i][j] += dp2[r][c]; } } } rep1(i,n){ auto [r,c] = a[i]; int ans = n-1+dp1[r][c]-1+dp2[r][c]-1; cout << ans << endl; } } int main() { fastio; int t = 1; // cin >> t; rep1(i, t) { solve(i); } return 0; }
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