oj.uz

답안 #958232

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
958232 2024-04-05T08:17:09 Z Vladth11 함박 스테이크 (JOI20_hamburg) C++14
3 / 100
 3000 ms 12044 KB 
#include <bits/stdc++.h>
#define debug(x) cerr << #x << " " << x << "\n"
#define debugs(x) cerr << #x << " " << x << " "
#pragma GCC optimize ("Ofast")
#pragma GCC target ("avx2")

#define int ll

using namespace std;
typedef long long ll;
typedef pair <ll, ll> pii;

const ll NMAX = 1000001;
const ll INF = 1e9;
const ll nrbits = 20;
const ll MOD = 998244353;

struct rect {
    int x1, y1, x2, y2;
} q[NMAX];

rect buckets[11];
int last[NMAX];

rect combine(rect a, rect b){
    rect sol = {max(a.x1, b.x1), max(a.y1, b.y1), min(a.x2, b.x2), min(a.y2, b.y2)};
    return sol;
}

signed main() {
#ifdef HOME
    ifstream cin(".in");
    ofstream cout(".out");
#endif // HOME
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);
    int n, i, k;
    cin >> n >> k;
    queue <int> qq;
    for(i = 1; i <= n; i++) {
        cin >> q[i].x1 >> q[i].y1 >> q[i].x2 >> q[i].y2;
        qq.push(i);
    }
    for(int j = 1; j <= k; j++) {
        buckets[j] = {0, 0, INF, INF};
    }
    int cnt = 0;
    while(qq.size()) {
        int acum = qq.front();
        qq.pop();
        if(cnt == last[acum]) {
            int oke = 0;
            for(int j = 1; j <= k; j++) {
                rect inters = combine(q[acum], buckets[j]);
                if(inters.x1 <= inters.x2 && inters.y1 <= inters.y2){
                    buckets[j] = inters;
                    oke = 1;
                    break;
                }
            }
            if(!oke) qq.push(acum);
            else
                cnt++;
        }else{
            int oke = 0;
            int care = 0;
            for(int j = 1; j <= k; j++) {
                rect inters = combine(q[acum], buckets[j]);
                if(inters.x1 <= inters.x2 && inters.y1 <= inters.y2){
                    care = j;
                    oke++;
                }
            }
            if(oke == 1){
                buckets[care] = combine(q[acum], buckets[care]);
                cnt++;
            }else{
                qq.push(acum); /// oke sigur e mai mare ca 0
            }
        }
        last[acum] = cnt;
    }
    for(i = 1; i <= k; i++){
        cout << buckets[i].x1 << " " << buckets[i].y1 << "\n";
    }
    return 0;
}

Subtask #1
1.0 / 1.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 2396 KB Output is correct
2 Correct 1 ms 2396 KB Output is correct
3 Correct 1 ms 2396 KB Output is correct
4 Correct 1 ms 2396 KB Output is correct

Subtask #2
1.0 / 1.0

# 결과 실행 시간 메모리 Grader output
1 Correct 13 ms 2548 KB Output is correct
2 Correct 3 ms 2552 KB Output is correct
3 Correct 4 ms 2396 KB Output is correct
4 Correct 2 ms 2392 KB Output is correct

Subtask #3
0 / 3.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 3054 ms 2396 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #4
0 / 6.0

# 결과 실행 시간 메모리 Grader output
1 Correct 59 ms 2396 KB Output is correct
2 Execution timed out 3060 ms 2396 KB Time limit exceeded
3 Halted 0 ms 0 KB -

Subtask #5
1.0 / 1.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 2396 KB Output is correct
2 Correct 1 ms 2396 KB Output is correct
3 Correct 1 ms 2396 KB Output is correct
4 Correct 1 ms 2396 KB Output is correct
5 Correct 66 ms 12044 KB Output is correct
6 Correct 65 ms 11856 KB Output is correct
7 Correct 65 ms 11856 KB Output is correct
8 Correct 66 ms 11672 KB Output is correct

Subtask #6
0 / 3.0

# 결과 실행 시간 메모리 Grader output
1 Correct 13 ms 2548 KB Output is correct
2 Correct 3 ms 2552 KB Output is correct
3 Correct 4 ms 2396 KB Output is correct
4 Correct 2 ms 2392 KB Output is correct
5 Execution timed out 3028 ms 11604 KB Time limit exceeded
6 Halted 0 ms 0 KB -

Subtask #7
0 / 6.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 3054 ms 2396 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #8
0 / 79.0

# 결과 실행 시간 메모리 Grader output
1 Correct 59 ms 2396 KB Output is correct
2 Execution timed out 3060 ms 2396 KB Time limit exceeded
3 Halted 0 ms 0 KB -