제출 #957118

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
957118		vjudge1	Detecting Molecules (IOI16_molecules)	C++17	9 / 100	1 ms	600 KiB

molecules

#include <bits/stdc++.h>
using namespace std;
#define sst string
#define REP(i,x,y) for(ll i=x;i<=y;i++)
#define freeopen   freopen("input.txt","r",stdin); freopen("output.txt","w",stdout);
#define mod 1000000007
#define pb push_back
#define mk make_pair
#define ll long long
#define foor(x,vec) for(auto x:vec ){cout<<x<<" ";}
#define fi first
#define se second
#define MAXN 1000069
#define lld long double
#define cha ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
#define ffl fflush(stdout)
#define pii pair<ll,ll>
ll mvx[]={1,-1,0,0};
ll mvy[]={0,0,-1,1};

vector <int> find_subset(int l,int u,vector<int> a){
    int n=a.size();
    vector<int> ans;
    int sum=0;
    for(int i=0;i<n;i++){
        if(sum+a[i]<=u){
            sum+=a[i];
            ans.pb(i);
        }
    }
    if(l<=sum && sum<=u){
        return ans;
    }
    else{
        ans.clear();
        return ans;
    }
}

/*
---------------------------------------------------go get gold---------------------------------------------------------------------
- If u see the problem dp there's many option to iterate, u can iterate from 1- n or 1 - (possible max number)
- If u see the problem that has unexpected constraint u can divide it into 2 problem
- If u see the problem that can use binary search, then u can use binser + check condition
- in interactive problem there's many trick using binser
- kalo misal mau cari yang sama pake pernah ke visit ga bilangan itu
- kalo problem yang high itu biasanya optimisasi nya pake 2 array
- dp bisa aja kek kamu tenzing balls dimana optimisasi 2 dp
- janlup fibonacci
- kalo binser mending r = 3 * 1e18 aja
- kalo mau dibalik itu pake value nya tinggal diubah ke size
 */

• Subtask 1: 9 / 9
• Subtask 2: 0 / 10
• Subtask 3: 0 / 12
• Subtask 4: 0 / 15
• Subtask 5: 0 / 23
• Subtask 6: 0 / 31