oj.uz

답안 #953589

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
953589 2024-03-26T09:44:54 Z Parsa_Fallahpour Growing Vegetable is Fun 3 (JOI19_ho_t3) C++17
0 / 100
 500 ms 1048576 KB 
/*
    Sag Template by ParsaF(RBS Master)
*/
 
// Heaven
 
#include <bits/stdc++.h>

#pragma GCC optimize("O3,unroll-loops")
//#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
#pragma GCC target("sse4")

using namespace std;

 
#define TOF_IO                                   ios_base::sync_with_stdio(false);cin.tie(0) , cout.tie(0);
#define File_IO(x,y)                             freopen(x, "r", stdin); freopen(y, "w", stdout);
 
#define SEP                                      ' '
#define endl                                     '\n'
 
#define F                                        first
#define S                                        second
#define ALL(x)                                   (x).begin(), (x).end()
#define sz(x)                                    (x).size()
#define PB                                       push_back
#define MP(x, y)                                 make_pair(x, y)
 
#define toLower(x)                               transform(ALL(x), x.begin(), ::tolower)
#define toUpper(x)                               transform(ALL(x), x.begin(), ::toupper)
 
#define EDGE(arr, x, y)                          arr[x].PB(y), arr[y].PB(x)
#define WEDGE(arr, x, y, z)                      arr[x].PB({y, z}), arr[y].PB({x, z})
 
#define debug(x)                                 cerr << #x << ": " << x << endl
#define kill(x)                                  cout << x << endl, exit(0);
 
#define BIPC(x)                                  __builtin_popcount(x)
 
#define fD1(arr, ind, x)                         for(int i=0; i<ind; i++) arr[i] = x;
#define fD2(arr, ind1, ind2, x)                  for(int i=0; i<ind1; i++) for(int j=0; j<ind2; j++) arr[i][j] = x;
 
#define lc                                       (id << 1)
#define rc                                       ((id << 1) | 1)
#define isLeaf                                   r - l == 1

typedef long long       ll; 
typedef long double     lld;
typedef pair<ll, ll>    pll;
typedef pair<int, int>  pii;
 
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
 
const ll N    = 4e2 + 10;
const ll MAXN = 1023;
const ll MT   = 323 + 0;
const ll sq   = 320;
 
const ll M    = 1e9 + 7;
const ll IM   = 1e9 + 9;
 
const ll LOG  = 11;
 
const ll INF  = 1e16 + 1; 
const lld EPS = 0.0000001;
 
ll prime[] = {1000000009, 1000000007, 988244353, 1000696969, 696969569, 1223232323};
 
 
/***********************************************************       Dark side of Heaven        ************************************************************/
 
/***************************************************************************************************************************************************/
 
 
ll POW(ll a, ll b, ll md); 
ll LIS(vector<ll>& v);
ll MOD(ll a, ll b);
 
void YES(bool flag);
void Yes(bool flag);
 
inline ll mod_add(ll a, ll b);
inline ll mod_neg(ll a, ll b);
inline ll mod_mlt(ll a, ll b);
 
/*
ll factI[N + 1], Numi[N + 1], fact[N + 1];
void InverseofNumber(ll p); void InverseofFactorial(ll p); void factorial(ll p); ll nPr(ll N, ll R, ll p); ll nCr(ll N, ll R); void comb();
*/

ll n;

string s;

vector<ll> R, G, B;


ll dp[N][N][N][3];

ll AB(ll x)
{
    if(x<0) return 0;
    return x;
}

void solve()
{
    cin >> n;
    
    cin >> s;
    s = "$" + s;
    for(int i=1; i<=n; i++)
    {
        if(s[i] == 'R') R.PB(i);
        if(s[i] == 'G') G.PB(i);
        if(s[i] == 'Y') B.PB(i);
    }
    
    for(int i=0; i<=n; i++) for(int j=0; j<=n; j++) for(int k=0; k<=n; k++) for(int f=0; f<3; f++) dp[i][j][k][f] = INF;
    dp[0][0][0][0] = 0;
    dp[0][0][0][1] = 0;
    dp[0][0][0][2] = 0;
    
    for(int i=0; i<n; i++)
    {
        for(int r=0; r<=i; r++)
        {
            for(int g=0; g<=i-r; g++)
            {
                ll b = i-g-r;
                if(sz(R) >= r+1) dp[r+1][g][b][0] = min(dp[r+1][g][b][0], min(dp[r][g][b][1], dp[r][g][b][2]) + AB(i+1-R[r]));
                if(sz(G) >= g+1) dp[r][g+1][b][1] = min(dp[r][g+1][b][1], min(dp[r][g][b][0], dp[r][g][b][2]) + AB(i+1-G[g]));
                if(sz(B) >= b+1) dp[r][g][b+1][2] = min(dp[r][g][b+1][2], min(dp[r][g][b][0], dp[r][g][b][1]) + AB(i+1-B[b]));
                
            }
        }
    }
    ll ans = min({dp[sz(R)][sz(G)][sz(B)][0], dp[sz(R)][sz(G)][sz(B)][1], dp[sz(R)][sz(G)][sz(B)][2]});
    
    cout << (ans == INF? -1 : ans) << endl;
}
 
/*
*/
 
int main()
{
    TOF_IO;
    
    ll nTest=1;
    //cin >> nTest;
    
    while(nTest--) solve();
	
    return 0;
}
 
/********************************************************       The line that separates heaven and hell        *******************************************************/
 
// HELL
/*
void InverseofNumber(ll p = M){Numi[0] = Numi[1] = 1; for (ll i = 2; i <= N; i++){Numi[i] = Numi[p % i] * (p - p / i) % p;}}
void InverseofFactorial(ll p = M){factI[0] = factI[1] = 1;for (ll i = 2; i <= N; i++){factI[i] = (Numi[i] * factI[i - 1]) % p;}}
void factorial(ll p = M){fact[0] = 1;for (ll i = 1; i <= N; i++){fact[i] = (fact[i - 1] * i) % p;}}
ll nPr(ll N, ll R, ll p = M){if (N - R < 0 || R < 0) {return 0;}int ans = ((fact[N]) % p * factI[N - R]) % p;return ans;}
ll nCr(ll N, ll R){if (N - R < 0 || R < 0) {return 0;}int ans = ((fact[N] * factI[R]) % M * factI[N - R]) % M;return ans;}
void comb(){ll p = M;InverseofNumber(p);InverseofFactorial(p);factorial(p);}
*/
 
ll POW(ll a, ll b, ll md) {return (!b ? 1 : (b & 1 ? MOD(a * POW(MOD(a * a, md), b / 2, md), md) : MOD(POW(MOD(a * a, md), b / 2, md), md)));}
ll MOD(ll a, ll b){return (a%b + b) % b;}
 
ll LIS(vector<ll>& v){if (v.size() == 0) {return 0;} vector<ll> tail(v.size(), 0); ll length = 1; tail[0] = v[0]; for (int i = 1; i < v.size(); i++) {auto b = tail.begin(), e = tail.begin() + length; auto it = lower_bound(b, e, v[i]); if (it == tail.begin() + length){tail[length++] = v[i];}else{*it = v[i];}} return length;}
 
void YES(bool flag){cout << (flag? "YES\n" : "NO\n");}
void Yes(bool flag){cout << (flag? "Yes\n" : "No\n");}
 
inline ll mod_add(ll a, ll b){ ll res = a + b; return (res >= M? res - M : res); }
inline ll mod_neg(ll a, ll b){ ll res = (abs(a - b) < M? a - b : (a - b) % M); return (res < 0? res + M : res); }
inline ll mod_mlt(ll a, ll b){ return (a * b % M); }

Compilation message

joi2019_ho_t3.cpp: In function 'void solve()':
joi2019_ho_t3.cpp:131:26: warning: comparison of integer expressions of different signedness: 'std::vector<long long int>::size_type' {aka 'long unsigned int'} and 'int' [-Wsign-compare]
  131 |                 if(sz(R) >= r+1) dp[r+1][g][b][0] = min(dp[r+1][g][b][0], min(dp[r][g][b][1], dp[r][g][b][2]) + AB(i+1-R[r]));
      |                          ^
joi2019_ho_t3.cpp:132:26: warning: comparison of integer expressions of different signedness: 'std::vector<long long int>::size_type' {aka 'long unsigned int'} and 'int' [-Wsign-compare]
  132 |                 if(sz(G) >= g+1) dp[r][g+1][b][1] = min(dp[r][g+1][b][1], min(dp[r][g][b][0], dp[r][g][b][2]) + AB(i+1-G[g]));
      |                          ^
joi2019_ho_t3.cpp:133:26: warning: comparison of integer expressions of different signedness: 'std::vector<long long int>::size_type' {aka 'long unsigned int'} and 'll' {aka 'long long int'} [-Wsign-compare]
  133 |                 if(sz(B) >= b+1) dp[r][g][b+1][2] = min(dp[r][g][b+1][2], min(dp[r][g][b][0], dp[r][g][b][1]) + AB(i+1-B[b]));
      |                          ^
joi2019_ho_t3.cpp: In function 'll LIS(std::vector<long long int>&)':
joi2019_ho_t3.cpp:173:133: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<long long int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
  173 | ll LIS(vector<ll>& v){if (v.size() == 0) {return 0;} vector<ll> tail(v.size(), 0); ll length = 1; tail[0] = v[0]; for (int i = 1; i < v.size(); i++) {auto b = tail.begin(), e = tail.begin() + length; auto it = lower_bound(b, e, v[i]); if (it == tail.begin() + length){tail[length++] = v[i];}else{*it = v[i];}} return length;}
      |                                                                                                                                   ~~^~~~~~~~~~

Subtask #1
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 2396 KB Output is correct
2 Correct 2 ms 4444 KB Output is correct
3 Correct 1 ms 6492 KB Output is correct
4 Correct 5 ms 21040 KB Output is correct
5 Correct 6 ms 33372 KB Output is correct
6 Correct 5 ms 33340 KB Output is correct
7 Correct 4 ms 33372 KB Output is correct
8 Correct 4 ms 33112 KB Output is correct
9 Correct 4 ms 33372 KB Output is correct
10 Correct 5 ms 33368 KB Output is correct
11 Incorrect 5 ms 33236 KB Output isn't correct
12 Halted 0 ms 0 KB -

Subtask #2
0 / 55.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 2396 KB Output is correct
2 Correct 2 ms 4444 KB Output is correct
3 Correct 1 ms 6492 KB Output is correct
4 Correct 5 ms 21040 KB Output is correct
5 Correct 6 ms 33372 KB Output is correct
6 Correct 5 ms 33340 KB Output is correct
7 Correct 4 ms 33372 KB Output is correct
8 Correct 4 ms 33112 KB Output is correct
9 Correct 4 ms 33372 KB Output is correct
10 Correct 5 ms 33368 KB Output is correct
11 Incorrect 5 ms 33236 KB Output isn't correct
12 Halted 0 ms 0 KB -

Subtask #3
0 / 15.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 6488 KB Output is correct
2 Execution timed out 969 ms 1048576 KB Time limit exceeded
3 Halted 0 ms 0 KB -

Subtask #4
0 / 25.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 2396 KB Output is correct
2 Correct 2 ms 4444 KB Output is correct
3 Correct 1 ms 6492 KB Output is correct
4 Correct 5 ms 21040 KB Output is correct
5 Correct 6 ms 33372 KB Output is correct
6 Correct 5 ms 33340 KB Output is correct
7 Correct 4 ms 33372 KB Output is correct
8 Correct 4 ms 33112 KB Output is correct
9 Correct 4 ms 33372 KB Output is correct
10 Correct 5 ms 33368 KB Output is correct
11 Incorrect 5 ms 33236 KB Output isn't correct
12 Halted 0 ms 0 KB -