Submission #949604

#	Time	Username	Problem	Language	Result	Execution time	Memory
949604		GrindMachine	Sailing Race (CEOI12_race)	C++17	40 / 100	3100 ms	5836 KiB

race

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

using namespace std;
using namespace __gnu_pbds;

template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
typedef long long int ll;
typedef long double ld;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;

#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL)
#define pb push_back
#define endl '\n'
#define sz(a) (int)a.size()
#define setbits(x) __builtin_popcountll(x)
#define ff first
#define ss second
#define conts continue
#define ceil2(x,y) ((x+y-1)/(y))
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define yes cout << "Yes" << endl
#define no cout << "No" << endl

#define rep(i,n) for(int i = 0; i < n; ++i)
#define rep1(i,n) for(int i = 1; i <= n; ++i)
#define rev(i,s,e) for(int i = s; i >= e; --i)
#define trav(i,a) for(auto &i : a)

template<typename T>
void amin(T &a, T b) {
    a = min(a,b);
}

template<typename T>
void amax(T &a, T b) {
    a = max(a,b);
}

#ifdef LOCAL
#include "debug.h"
#else
#define debug(x) 42
#endif

/*



*/

const int MOD = 1e9 + 7;
const int N = 500 + 5;
const int inf1 = int(1e9) + 5;
const ll inf2 = ll(1e18) + 5;

vector<int> adj[N];

void solve(int test_case)
{
    int n,k; cin >> n >> k;
    rep(u,n){
        while(true){
            int v; cin >> v;
            v--;
            if(v == -1) break;
            assert(u != v);
            adj[u].pb(v);
        }
    }

    vector<array<int,3>> order;
    rep(l,n){
        rep(r,n){
            int len = 0;
            if(l <= r){
                len = r-l+1;
            }
            else{
                len = n-l+r+1;
            }

            order.pb({len,l,r});
        }
    }

    sort(all(order));

    int dp[n][n][2];
    memset(dp,0,sizeof dp);

    auto in_range = [&](int i, int l, int r){
        if(l <= r){
            return i >= l and i <= r;
        }
        else{
            return i >= l or i <= r;
        }
    };

    for(auto [len,l,r] : order){
        if(l == r){
            rep(j,2){
                int u = 0;
                if(!j) u = l-1;
                else u = r+1;
                u = (u%n+n)%n;

                trav(v,adj[u]){
                    if(v == l){
                        dp[l][r][j] = 1;
                    }
                }
            }
        }
        else{
            rep(j,2){
                int u = 0;
                if(!j) u = l-1;
                else u = r+1;
                u = (u%n+n)%n;

                trav(v,adj[u]){
                    if(!in_range(v,l,r)) conts;

                    int val = 0;
                    if(v != l){
                        amax(val,dp[l][(v-1+n)%n][1]);
                    }
                    if(v != r){
                        amax(val,dp[(v+1)%n][r][0]);
                    }

                    val++;
                    amax(dp[l][r][j],val);
                }
            }
        }
    }

    pii ans = {0,0};

    rep(u,n){
        trav(v,adj[u]){
            int val = 0;
            if((u+1)%n != v){
                amax(val,dp[(u+1)%n][(v-1+n)%n][1]);
            }
            if((v+1)%n != u){
                amax(val,dp[(v+1)%n][(u-1+n)%n][0]);
            }

            val++;
            pii px = {val,u};
            amax(ans,px);
        }
    }

    if(!k){
        ans.ss++;
        cout << ans.ff << endl << ans.ss << endl;
        return;
    }

    vector<int> dp2(n);
    vector<bool> active(n);

    rep(u,n){
        trav(v,adj[u]){
            vector<int> order1, order2;
            for(int i = (u+1)%n; i != v; i = (i+1)%n){
                order1.pb(i);
            }
            for(int i = (v+1)%n; i != u; i = (i+1)%n){
                order2.pb(i);
            }

            if(order1.empty() or order2.empty()) conts;

            reverse(all(order1));
            order1.insert(order1.begin(),v);
            order2.insert(order2.begin(),v);

            fill(all(dp2),-inf1);
            dp2[v] = 0;
            trav(x,order1) active[x] = 1;

            trav(x,order1){
                active[x] = 0;
                trav(y,adj[x]){
                    if(active[y]){
                        amax(dp2[y],dp2[x]+1);
                    }
                }
            }

            trav(x,order2) active[x] = 1;

            trav(x,order2){
                active[x] = 0;
                trav(y,adj[x]){
                    if(active[y]){
                        amax(dp2[y],dp2[x]+1);
                    }
                }
            }

            trav(x,order2) active[x] = 1;

            trav(x,order1){
                trav(y,adj[x]){
                    if(active[y]){
                        int l = (v+1)%n, r = (u-1+n)%n;
                        int val = 0;
                        if(y != l){
                            amax(val,dp[l][(y-1+n)%n][1]);
                        }
                        if(y != r){
                            amax(val,dp[(y+1)%n][r][0]);
                        }

                        val += 2+dp2[x];
                        pii px = {val,u};
                        amax(ans,px);
                    }
                }
            }

            trav(x,order2) active[x] = 0;
            trav(x,order1) active[x] = 1;

            trav(x,order2){
                trav(y,adj[x]){
                    if(active[y]){
                        int l = (u+1)%n, r = (v-1+n)%n;
                        int val = 0;
                        if(y != l){
                            amax(val,dp[l][(y-1+n)%n][1]);
                        }
                        if(y != r){
                            amax(val,dp[(y+1)%n][r][0]);
                        }

                        val += 2+dp2[x];
                        pii px = {val,u};
                        amax(ans,px);
                    }
                }
            }

            trav(x,order1) active[x] = 0;
        }
    }

    ans.ss++;
    cout << ans.ff << endl << ans.ss << endl;
}

int main()
{
    fastio;

    int t = 1;
    // cin >> t;

    rep1(i, t) {
        solve(i);
    }

    return 0;
}

• Subtask 1: 40 / 100