제출 #947507

#제출 시각아이디문제언어결과실행 시간메모리
947507GrindMachineCubeword (CEOI19_cubeword)C++17
21 / 100
182 ms9560 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) (int)a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x,y) ((x+y-1)/(y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i,n) for(int i = 0; i < n; ++i) #define rep1(i,n) for(int i = 1; i <= n; ++i) #define rev(i,s,e) for(int i = s; i >= e; --i) #define trav(i,a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a,b); } template<typename T> void amax(T &a, T b) { a = max(a,b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* */ const int MOD = 998244353; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; void solve(int test_case) { ll n; cin >> n; vector<string> a(n); rep(i,n) cin >> a[i]; rep(i,n){ auto s = a[i]; reverse(all(s)); a.pb(s); } sort(all(a)); a.resize(unique(all(a))-a.begin()); n = sz(a); ll alpha = 6; ll cnt[15][alpha][alpha]; memset(cnt,0,sizeof cnt); rep(i,n){ auto &s = a[i]; cnt[sz(s)][s[0]-'a'][s.back()-'a']++; } ll ans = 0; for(int len = 3; len <= 10; ++len){ auto &f = cnt[len]; rep(x1,alpha){ rep(y1,alpha){ rep(x2,alpha){ rep(y2,alpha){ rep(x3,alpha){ rep(y3,alpha){ rep(x4,alpha){ rep(y4,alpha){ ll mul1 = f[x1][y1]*f[x2][y2]%MOD*f[x3][y3]%MOD*f[x4][y4]%MOD; ll mul2 = f[x1][x2]*f[x2][x3]%MOD*f[x3][x4]%MOD*f[x4][x1]%MOD; ll mul3 = f[y1][y2]*f[y2][y3]%MOD*f[y3][y4]%MOD*f[y4][y1]%MOD; ll add = mul1*mul2%MOD*mul3%MOD; ans = (ans+add)%MOD; } } } } } } } } } cout << ans << endl; } int main() { fastio; int t = 1; // cin >> t; rep1(i, t) { solve(i); } return 0; }
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