이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "bits/stdc++.h"
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
using namespace std;
#define int long long
#define ff first
#define ss second
#define pb push_back
#define all(x) x.begin(),x.end()
#define ordered_mset tree<int, null_type,less_equal<int>, rb_tree_tag,tree_order_statistics_node_update>
#define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update>
const double INF = 1e4;
int binpow (int a, int n) {
if (n == 0)
return 1;
if (n % 2 == 1)
return binpow (a, n-1) * a;
else {
int b = binpow (a, n/2);
return b * b;
}
}
void solve(){
int n;
cin >> n;
double a[n],b[n];
for(int i = 0;i < n;i++){
cin >> a[i] >> b[i];
}
double ans = 0;
for(int fst = 0;fst < (1 << n);fst++){
for(int scn = 0;scn < (1 << n);scn++){
double sum1 = 0;
double sum2 = 0;
int cnt = 0;
for(int i = 0;i < n;i++){
if(fst >> i & 1){
cnt++;
sum1 += a[i];
}
}
for(int i = 0;i < n;i++){
if(scn >> i & 1){
cnt++;
sum2 += b[i];
}
}
ans = max(ans,min(sum1 - cnt,sum2 - cnt));
}
}
cout << fixed << setprecision(4);
cout << ans << "\n";
}
signed main(){
ios_base::sync_with_stdio(0);
cin.tie(0),cout.tie(0);
int t = 1;
// cin >> t;
while(t--){
solve();
}
}
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