이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<string.h>
#include<stdio.h>
#include<utility>
#include<queue>
#define N 30000
#define S 170
#define N1 2*(S*N+N+N)
int lo(int a,int b){return a<b?a:b;}
int z=1e9,n,m,b[N],p[N],e[N1][3],ne,h[N1],d[N1];
void link(int u,int v,int w) {e[++ne][0]=v,e[ne][1]=w,e[ne][2]=h[u],h[u]=ne;}
int bp(int bb,int pp){return bb+30000*pp+30000;}
int main()
{
scanf("%d%d",&n,&m);
for(int i=0;i<m;++i){
scanf("%d%d",b+i,p+i);
if(p[i]<S){
link(b[i],bp(b[i],p[i]),0);
}else{
for(int dd=1,j=b[i]-p[i];j>=0;j-=p[i],++dd)link(b[i],j,dd);
for(int dd=1,j=b[i]+p[i];j<n;j+=p[i],++dd)link(b[i],j,dd);
}
}
memset(d,63,sizeof d);
std::priority_queue<std::pair<int,int>>pq;
pq.emplace(-(d[b[0]]=0),b[0]);
while(pq.size())
{
auto[c,u]=pq.top();c=-c;pq.pop();
if(d[u]-c)continue;
for(int j=h[u];j;j=e[j][2])if(d[e[j][0]]>c+e[j][1])
pq.emplace(-(d[e[j][0]]=c+e[j][1]),e[j][0]);
if(u>=30000){
int bb,pp;
bb=(u-30000)%30000;
pp=(u-30000)/30000;
if(bb==b[1])z=lo(z,c);
if(d[bb]>c)pq.emplace(-(d[bb]=c),bb);
if(bb>=pp&&d[bp(bb-pp,pp)]>c+1)pq.emplace(-(d[bp(bb-pp,pp)]=c+1),bp(bb-pp,pp));
if(bb+pp<n&&d[bp(bb+pp,pp)]>c+1)pq.emplace(-(d[bp(bb+pp,pp)]=c+1),bp(bb+pp,pp));
} else if(u==b[1])z=lo(z,c);
}
if(z<1e9)printf("%d",z);else puts("-1");
}
컴파일 시 표준 에러 (stderr) 메시지
skyscraper.cpp: In function 'int main()':
skyscraper.cpp:16:10: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
16 | scanf("%d%d",&n,&m);
| ~~~~~^~~~~~~~~~~~~~
skyscraper.cpp:18:14: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
18 | scanf("%d%d",b+i,p+i);
| ~~~~~^~~~~~~~~~~~~~~~
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