이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define f first
#define s second
#define pb push_back
#define ep emplace
#define eb emplace_back
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define uniquev(v) sort(all(v)), (v).resize(unique(all(v)) - (v).begin())
#define mem(f,x) memset(f , x , sizeof(f))
#define sz(x) (int)(x).size()
#define __lcm(a, b) (1ll * ((a) / __gcd((a), (b))) * (b))
#define mxx *max_element
#define mnn *min_element
#define cntbit(x) __builtin_popcountll(x)
#define len(x) (int)(x.length())
const int N = 100 + 10;
ll dis[N][N], profit[N][N];
ll b[N][1000 + 10], s[N][1000 + 10], n;
ll bin(ll m) {
vector < vector <ll>> dd(n + 1, vector <ll> (n + 1, -1e17));
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= n; j++) {
dd[i][j] = profit[i][j] - dis[i][j] * m;
}
}
for (int k = 1; k <= n; k++) {
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= n; j++) {
dd[i][j] = max(dd[i][j], dd[i][k] + dd[k][j]);
}
}
}
for (int i = 1; i <= n; i++) {
if (dd[i][i] >= 0) {
return 1;
}
}
return 0;
}
ll solve() {
int m, k;
cin >> n >> m >> k;
for (int i = 1; i <= n; i++) {
fill(dis[i], dis[i] + n + 1, 1e11);
}
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= k; j++) {
cin >> b[i][j] >> s[i][j];
}
}
for (int i = 1; i <= m; i++) {
ll a, b, c;
cin >> a >> b >> c;
dis[a][b] = min(dis[a][b], c);
}
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= n; j++) {
for (int f = 1; f <= k; f++) {
if (s[j][f] == -1 || b[i][f] == -1)
continue;
profit[i][j] = max(profit[i][j], s[j][f] - b[i][f]);
}
}
}
for (int k = 1; k <= n; k++) {
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= n; j++) {
dis[i][j] = min(dis[i][j], dis[i][k] + dis[k][j]);
}
}
}
ll l = 0, r = 2e7 + 100, ans = 0;
while (l <= r) {
ll m = (l + r) / 2;
if (bin(m)) {
ans = m;
l = m + 1;
} else {
r = m - 1;
}
}
return ans;
}
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int t = 1;
//cin >> t;
while (t--) {
//solve();
cout << solve() << '\n';
}
}
/*
4 5 2
10 9 5 2
6 4 20 15
9 7 10 9
-1 -1 16 11
1 2 3
2 3 3
1 4 1
4 3 1
3 1 1
*/
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