이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
//抄解因為我笨,根本就不會最短路徑樹
//煩躁實作
#include <bits/stdc++.h>
using namespace std;
#define int long long
#define pii pair<int,int>
#define fs first
#define sc second
const int inf = 1e18, binf = inf + 11e9;
pii es[40100];
int n, m, C[40100], D[40100], hase[210][210] = {0}, eid[210][210] = {0}, ontree[40100] = {0};
vector <int> ans1n, ansn1, tree1n, treen1;
pair< vector<int>, vector<int> > Dijkstra(int st, int ed);
int solve (int ei) {
if (ontree[ei]) {
int tmp = eid[es[ei].sc][es[ei].fs], tmp2 = hase[es[ei].sc][es[ei].fs];
hase[es[ei].fs][es[ei].sc] = 0, hase[es[ei].sc][es[ei].fs] = 1;
eid[es[ei].sc][es[ei].fs] = eid[es[ei].fs][es[ei].sc];
swap(es[ei].fs, es[ei].sc);
int res = Dijkstra(1, n).fs[n] + Dijkstra(n, 1).fs[1] + D[ei];
swap(es[ei].fs, es[ei].sc);
hase[es[ei].fs][es[ei].sc] = 1, hase[es[ei].sc][es[ei].fs] = tmp2;
eid[es[ei].sc][es[ei].fs] = tmp;
return res;
}
else {
int res = min(ans1n[n] + ansn1[es[ei].fs] + ansn1[es[ei].sc], ans1n[es[ei].sc] + ans1n[es[ei].fs] + ansn1[1]) + C[ei] + D[ei];
res = min(res, ansn1[es[ei].fs] + ansn1[es[ei].sc] + ans1n[es[ei].sc] + ans1n[es[ei].fs] + C[ei] * 2 + D[ei]);
return res;
}
}
pair< vector<int>, vector<int> > Dijkstra(int st, int ed) {
vector <int> ans(n + 2, binf), vis(n + 2, 0), tree, from(n + 2, 0);
ans[st] = 0;
for (int t = 0; t <= n; t++) {
int ii = 1;
for (int i = 1; i <= n; i++) if (!vis[i]) ii = i;
for (int i = 1; i <= n; i++) if (!vis[i] and ans[i] < ans[ii]) ii = i;
if (vis[ii] or ans[ii] > inf) break;
vis[ii] = 1;
for (int j = 1; j <= n; j++) {
if (vis[j] or !hase[ii][j]) continue;
int ei = eid[ii][j];
if (ans[ii] + C[ei] < ans[j]) {
ans[j] = ans[ii] + C[ei];
from[j] = ei;
}
}
}
for (int i = 1; i <= n; i++) if(i != st) tree.push_back(from[i]);
return {ans, tree};}
signed main () {
// ios_base :: sync_with_stdio(false); cin.tie(0);
cin >> n >> m;
for (int i = 0; i < m; i++) {
cin >> es[i].fs >> es[i].sc >> C[i] >> D[i];
hase[es[i].fs][es[i].sc] = 1, eid[es[i].fs][es[i].sc] = i;
}
auto rEs = Dijkstra (1, n);
ans1n = rEs.fs, tree1n = rEs.sc;
rEs = Dijkstra (n, 1);
ansn1 = rEs.fs, treen1 = rEs.sc;
for (int x : tree1n) ontree[x] = 1;
for (int x : treen1) ontree[x] = 1;
int finans = ans1n[n] + ansn1[1];
for (int i = 0; i < m; i++) finans = min(finans, solve(i));
if (finans >= inf) finans = -1;
cout << finans << '\n';
return 0;}
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