Submission #924688

#TimeUsernameProblemLanguageResultExecution timeMemory
924688NK_Sure Bet (CEOI17_sure)C++17
0 / 100
0 ms348 KiB
// Success consists of going from failure to failure without loss of enthusiasm #include <bits/stdc++.h> using namespace std; #define nl '\n' #define pb push_back #define sz(x) int(x.size()) using db = double; using ll = long long; template<class T> using V = vector<T>; using vd = V<db>; int main() { cin.tie(0)->sync_with_stdio(0); int N; cin >> N; vd A(N), B(N); for(int i = 0; i < N; i++) { cin >> A[i] >> B[i]; } sort(rbegin(A), rend(A)); sort(rbegin(B), rend(B)); for(int i = 1; i < N; i++) A[i] += A[i - 1]; for(int i = 1; i < N; i++) B[i] += B[i - 1]; // for(auto& x : A) cout << x << " "; // cout << endl; // for(auto& x : B) cout << x << " "; // cout << endl; db ans = 0; for(int x = 2; x <= 2 * N; x++) { // cout << x << " ===> " << endl; // take x odds auto F = [&](int i) { if (i <= 0) return db(0); if (x - i <= 0) return db(0); return min(A[i - 1], B[x - 1 - i]) - x; }; int lo = max(0, x - N), hi = min(x, N); while(lo < hi) { int mid = (lo + hi + 1) / 2; if (A[mid - 1] < B[x - 1 - mid]) lo = mid; else hi = mid - 1; } ans = max(ans, F(lo)); ans = max(ans, F(lo - 1)); // maximize min_{1 <= i <= x}(A[i - 1] - x, B[x - i] - x) } printf("%.4lf", ans); exit(0-0); }
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