oj.uz

답안 #92461

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
92461 2019-01-03T01:11:45 Z qkxwsm Min-max tree (BOI18_minmaxtree) C++14
58 / 100
 313 ms 52380 KB 
#pragma GCC optimize ("O3")
#pragma GCC target ("sse4")
#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/rope>

using namespace std;
using namespace __gnu_pbds;
using namespace __gnu_cxx;

random_device(rd);
mt19937 rng(rd());
const long long FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();

struct custom_hash
{
	template<class T>
	unsigned long long operator()(T v) const
	{
		unsigned long long x = v;
		x += FIXED_RANDOM;
		// x += 11400714819323198485ull;
		// x = (x ^ (x >> 30)) * 13787848793156543929ull;
		x = (x ^ (x >> 27)) * 10723151780598845931ull;
		return x ^ (x >> 31);
	}
};

template<class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
template<class T, class U> using hash_table = gp_hash_table<T, U, custom_hash>;

template<class T>
T randomize(T mod)
{
	return (uniform_int_distribution<T>(0, mod - 1))(rng);
}
template<class T>
void readi(T &x)
{
	x = 0;
	bool negative = false;
	char c = ' ';
	while (c < '-')
	{
		c = getchar();
	}
	if (c == '-')
	{
		negative = true;
		c = getchar();
	}
	while (c >= '0')
	{
		x = x * 10 + (c - '0');
		c = getchar();
	}
	if (negative)
	{
		x = -x;
	}
}
template<class T>
void printi(T output)
{
	if (output == 0)
	{
		putchar('0');
		return;
	}
	if (output < 0)
	{
		putchar('-');
		output = -output;
	}
	int buf[20], n = 0;
	while(output)
	{
		buf[n] = ((output % 10));
		output /= 10;
		n++;
	}
	for (n--; n >= 0; n--)
	{
		putchar(buf[n] + '0');
	}
	return;
}
template<class T>
void ckmin(T &a, T b)
{
	a = min(a, b);
}
template<class T>
void ckmax(T &a, T b)
{
	a = max(a, b);
}
long long expo(long long a, long long e, long long mod)
{
	return ((e == 0) ? 1 : ((expo(a * a % mod, e >> 1, mod)) * ((e & 1) ? a : 1) % mod));
}
template<class T, class U>
void nmod(T &x, U mod)
{
	if (x >= mod) x -= mod;
}
template<class T>
T gcd(T a, T b)
{
	return (b ? gcd(b, a % b) : a);
}

#define y0 ___y0
#define y1 ___y1
#define MP make_pair
#define PB push_back
#define LB lower_bound
#define UB upper_bound
#define fi first
#define se second
#define DBG(x) cerr << #x << " = " << (x) << endl
#define SZ(x) ((int) ((x).size()))
#define FOR(i, a, b) for (auto i = (a), i##__end__ = (b); i < i##__end__; i++)
#define FORD(i, a, b) for (auto i = (a) - 1, i##__end__ = (b); i >= i##__end__; i--)
#define ALL(x) (x).begin(), (x).end()

const long double PI = 4.0 * atan(1.0);
const long double EPS = 1e-9;

#define MAGIC 347
#define SINF 10007
#define CO 1000007
#define INF 1000000007
#define BIG 1000000931
#define LARGE 1696969696967ll
#define GIANT 2564008813937411ll
#define LLINF 2696969696969696969ll
#define MAXN 500013

typedef long long ll;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef pair<ld, ld> pdd;
typedef vector<int> vi;
typedef vector<ll> vl;
typedef vector<ld> vd;
typedef vector<pii> vpi;
typedef vector<pll> vpl;
typedef vector<pdd> vpd;

int N, K, T, V;
vi edge[MAXN];
pii bound[MAXN];
int parent[MAXN];
int ancestor[25][MAXN];
pii dup[25][MAXN];
int st[MAXN], ft[MAXN], depth[MAXN];
int ans[MAXN];
vpi edge1[MAXN];
bitset<MAXN> vis, VIS;

bool insubt(int u, int v)
{
	return (u == N) || (st[u] <= st[v] && st[v] <= ft[u]);
}
void dfs(int u)
{
	st[u] = ft[u] = T;
	T++;
	for (int v : edge[u])
	{
		if (v == parent[u]) continue;
		parent[v] = u;
		depth[v] = depth[u] + 1;
		dfs(v);
		ft[u] = ft[v];
	}
}
int lca(int u, int v)
{
	//how far up does v go before u
	if (insubt(v, u)) return -1;
	FORD(i, 20, 0)
	{
		if (!insubt(ancestor[i][v], u))
		{
			v = ancestor[i][v];
		}
	}
	return v;
}
void work(int u)
{
	if (vis[u]) return;
	vis[u] = true;
	for (pii p : edge1[u])
	{
		if (ans[p.se] != 0 && ans[p.se] != V - 1) continue;
		ans[p.se] = p.fi;
		work(p.fi);
	}
}

int32_t main()
{
	ios_base::sync_with_stdio(0); cin.tie(0);
	// cout << fixed << setprecision(10);
	// cerr << fixed << setprecision(10);
	// if (fopen("file.in", "r"))
	// {
	// 	freopen ("file.in", "r", stdin);
	// 	freopen ("file.out", "w", stdout);
	// }
	cin >> N;
	FOR(i, 0, N - 1)
	{
		int u, v; cin >> u >> v; u--; v--;
		edge[u].PB(v);
		edge[v].PB(u);
	}
	parent[0] = N; dfs(0);
	FOR(i, 0, 22)
	{
		ancestor[i][N] = N;
	}
	FOR(i, 0, N)
	{
		ancestor[0][i] = parent[i];
		dup[0][i] = {-INF, INF};
	}
	FOR(i, 1, 21)
	{
		FOR(j, 0, N)
		{
			ancestor[i][j] = ancestor[i - 1][ancestor[i - 1][j]];
			dup[i][j] = {-INF, INF};
		}
	}
	cin >> K;
	while(K--)
	{
		int u, v, val;
		char typ;
		cin >> typ >> u >> v >> val; u--; v--;
		if (typ == 'm')
		{
			int w = lca(u, v), diff = depth[v] - depth[w] + 1;
			if (w != -1)
			{
				int x = v;
				FORD(i, 20, 0)
				{
					if (diff & (1 << i))
					{
						ckmax(dup[i][x].fi, val);
						x = ancestor[i][x];
					}
				}
			}
			w = lca(v, u);
			if (w != -1)
			{
				int x = u, diff = depth[u] - depth[w] + 1;
				FORD(i, 20, 0)
				{
					if (diff & (1 << i))
					{
						ckmax(dup[i][x].fi, val);
						x = ancestor[i][x];
					}
				}
			}
		}
		if (typ == 'M')
		{
			int w = lca(u, v);
			if (w != -1)
			{
				int x = v, diff = depth[v] - depth[w] + 1;
				FORD(i, 20, 0)
				{
					if (diff & (1 << i))
					{
						ckmin(dup[i][x].se, val);
						x = ancestor[i][x];
					}
				}
			}
			w = lca(v, u);
			if (w != -1)
			{
				int x = u, diff = depth[u] - depth[w] + 1;
				FORD(i, 20, 0)
				{
					if (diff & (1 << i))
					{
						ckmin(dup[i][x].se, val);
						x = ancestor[i][x];
					}
				}
			}
		}
	}
	FORD(i, 20, 1)
	{
		FOR(j, 0, N)
		{
			ckmin(dup[i - 1][j].se, dup[i][j].se);
			ckmin(dup[i - 1][ancestor[i - 1][j]].se, dup[i][j].se);
			ckmax(dup[i - 1][j].fi, dup[i][j].fi);
			ckmax(dup[i - 1][ancestor[i - 1][j]].fi, dup[i][j].fi);
		}
	}
	FOR(i, 0, N)
	{
		bound[i] = dup[0][i];
		// cerr << bound[i].fi << ' ' << bound[i].se << endl;
	}
	vi compress;
	//you can have one or the other, but not both!
	FOR(i, 1, N)
	{
		compress.PB(bound[i].fi);
		compress.PB(bound[i].se);
	}
	compress.PB(-INF); compress.PB(INF);
	sort(ALL(compress));
	compress.erase(unique(ALL(compress)), compress.end());
	V = SZ(compress);
	FOR(i, 1, N)
	{
		bound[i].fi = LB(ALL(compress), bound[i].fi) - compress.begin();
		bound[i].se = LB(ALL(compress), bound[i].se) - compress.begin();
		if (bound[i] == MP(0, V - 1)) continue;
		edge1[bound[i].fi].PB({bound[i].se, i});
		edge1[bound[i].se].PB({bound[i].fi, i});
	}
	work(0);
	work(V - 1);
	FOR(i, 1, V - 1)
	{
		if (vis[i]) continue;
		for (pii p : edge1[i])
		{
			if (p.fi != 0 && p.fi != V - 1 && vis[p.fi])
			{
				assert(ans[p.se] == p.fi);
			}
		}
		pii p = edge1[i][0];
		ans[p.se] = i;
		// cerr << "ans" << p.se << " = " << i << endl;
		work(i);
	}
	FOR(i, 1, N)
	{
		VIS[ans[i]] = true;
	}
	FOR(i, 1, V - 1)
	{
		if (!VIS[i]) return 0;
	}
	FOR(i, 1, N)
	{
		cout << i + 1 << ' ' << parent[i] + 1 << ' ' << (ans[i] == 0 ? randomize(INF) : compress[ans[i]]) << '\n';
	}
	//we don't need to worry about 0 and V-1, but other ones we must satisfy
	// cerr << "time elapsed = " << (clock() / (CLOCKS_PER_SEC / 1000)) << " ms" << endl;
	return 0;
}
/* READ READ READ
* int overflow, maxn too small, special cases (n=1?, two distinct?), cin.tie() interactive
* reread the problem, try small cases
* note down possible sources of error as you go
* do smth instead of nothing
*/

Compilation message

minmaxtree.cpp: In function 'int32_t main()':
minmaxtree.cpp:249:48: warning: array subscript is below array bounds [-Warray-bounds]
    int w = lca(u, v), diff = depth[v] - depth[w] + 1;
                                         ~~~~~~~^

Subtask #1
7.0 / 7.0

# 결과 실행 시간 메모리 Grader output
1 Correct 24 ms 24184 KB Output is correct
2 Correct 23 ms 24312 KB Output is correct
3 Correct 25 ms 24184 KB Output is correct
4 Correct 24 ms 24188 KB Output is correct

Subtask #2
22.0 / 22.0

# 결과 실행 시간 메모리 Grader output
1 Correct 296 ms 51932 KB Output is correct
2 Correct 193 ms 50280 KB Output is correct
3 Correct 229 ms 51048 KB Output is correct
4 Correct 313 ms 52380 KB Output is correct
5 Correct 285 ms 50924 KB Output is correct
6 Correct 243 ms 50920 KB Output is correct
7 Correct 196 ms 50412 KB Output is correct

Subtask #3
29.0 / 29.0

# 결과 실행 시간 메모리 Grader output
1 Correct 135 ms 48620 KB Output is correct
2 Correct 147 ms 49008 KB Output is correct
3 Correct 171 ms 50028 KB Output is correct
4 Correct 164 ms 50664 KB Output is correct
5 Correct 180 ms 49004 KB Output is correct
6 Correct 201 ms 49516 KB Output is correct
7 Correct 172 ms 49064 KB Output is correct
8 Correct 152 ms 49132 KB Output is correct

Subtask #4
0 / 42.0

# 결과 실행 시간 메모리 Grader output
1 Correct 24 ms 24184 KB Output is correct
2 Correct 23 ms 24312 KB Output is correct
3 Correct 25 ms 24184 KB Output is correct
4 Correct 24 ms 24188 KB Output is correct
5 Correct 296 ms 51932 KB Output is correct
6 Correct 193 ms 50280 KB Output is correct
7 Correct 229 ms 51048 KB Output is correct
8 Correct 313 ms 52380 KB Output is correct
9 Correct 285 ms 50924 KB Output is correct
10 Correct 243 ms 50920 KB Output is correct
11 Correct 196 ms 50412 KB Output is correct
12 Correct 135 ms 48620 KB Output is correct
13 Correct 147 ms 49008 KB Output is correct
14 Correct 171 ms 50028 KB Output is correct
15 Correct 164 ms 50664 KB Output is correct
16 Correct 180 ms 49004 KB Output is correct
17 Correct 201 ms 49516 KB Output is correct
18 Correct 172 ms 49064 KB Output is correct
19 Correct 152 ms 49132 KB Output is correct
20 Incorrect 160 ms 48524 KB Unexpected end of file - int32 expected
21 Halted 0 ms 0 KB -