oj.uz

답안 #92459

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
92459 2019-01-03T01:01:17 Z qkxwsm Min-max tree (BOI18_minmaxtree) C++14
29 / 100
 330 ms 94960 KB 
#pragma GCC optimize ("O3")
#pragma GCC target ("sse4")
#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/rope>

using namespace std;
using namespace __gnu_pbds;
using namespace __gnu_cxx;

random_device(rd);
mt19937 rng(rd());
const long long FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();

struct custom_hash
{
	template<class T>
	unsigned long long operator()(T v) const
	{
		unsigned long long x = v;
		x += FIXED_RANDOM;
		// x += 11400714819323198485ull;
		// x = (x ^ (x >> 30)) * 13787848793156543929ull;
		x = (x ^ (x >> 27)) * 10723151780598845931ull;
		return x ^ (x >> 31);
	}
};

template<class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
template<class T, class U> using hash_table = gp_hash_table<T, U, custom_hash>;

template<class T>
T randomize(T mod)
{
	return (uniform_int_distribution<T>(0, mod - 1))(rng);
}
template<class T>
void readi(T &x)
{
	x = 0;
	bool negative = false;
	char c = ' ';
	while (c < '-')
	{
		c = getchar();
	}
	if (c == '-')
	{
		negative = true;
		c = getchar();
	}
	while (c >= '0')
	{
		x = x * 10 + (c - '0');
		c = getchar();
	}
	if (negative)
	{
		x = -x;
	}
}
template<class T>
void printi(T output)
{
	if (output == 0)
	{
		putchar('0');
		return;
	}
	if (output < 0)
	{
		putchar('-');
		output = -output;
	}
	int buf[20], n = 0;
	while(output)
	{
		buf[n] = ((output % 10));
		output /= 10;
		n++;
	}
	for (n--; n >= 0; n--)
	{
		putchar(buf[n] + '0');
	}
	return;
}
template<class T>
void ckmin(T &a, T b)
{
	a = min(a, b);
}
template<class T>
void ckmax(T &a, T b)
{
	a = max(a, b);
}
long long expo(long long a, long long e, long long mod)
{
	return ((e == 0) ? 1 : ((expo(a * a % mod, e >> 1, mod)) * ((e & 1) ? a : 1) % mod));
}
template<class T, class U>
void nmod(T &x, U mod)
{
	if (x >= mod) x -= mod;
}
template<class T>
T gcd(T a, T b)
{
	return (b ? gcd(b, a % b) : a);
}

#define y0 ___y0
#define y1 ___y1
#define MP make_pair
#define PB push_back
#define LB lower_bound
#define UB upper_bound
#define fi first
#define se second
#define DBG(x) cerr << #x << " = " << (x) << endl
#define SZ(x) ((int) ((x).size()))
#define FOR(i, a, b) for (auto i = (a), i##__end__ = (b); i < i##__end__; i++)
#define FORD(i, a, b) for (auto i = (a) - 1, i##__end__ = (b); i >= i##__end__; i--)
#define ALL(x) (x).begin(), (x).end()

const long double PI = 4.0 * atan(1.0);
const long double EPS = 1e-9;

#define MAGIC 347
#define SINF 10007
#define CO 1000007
#define INF 1000000007
#define BIG 1000000931
#define LARGE 1696969696967ll
#define GIANT 2564008813937411ll
#define LLINF 2696969696969696969ll
#define MAXN 500013

typedef long long ll;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef pair<ld, ld> pdd;
typedef vector<int> vi;
typedef vector<ll> vl;
typedef vector<ld> vd;
typedef vector<pii> vpi;
typedef vector<pll> vpl;
typedef vector<pdd> vpd;

int N, K, T, V;
vi edge[MAXN];
pii bound[MAXN];
int parent[MAXN];
int ancestor[25][MAXN];
pii dup[25][MAXN];
int st[MAXN], ft[MAXN], depth[MAXN];
int ans[MAXN];
vpi edge1[MAXN];
bitset<MAXN> vis, VIS;

bool insubt(int u, int v)
{
	return (u == N) || (st[u] <= st[v] && st[v] <= ft[u]);
}
void dfs(int u)
{
	st[u] = ft[u] = T;
	T++;
	for (int v : edge[u])
	{
		if (v == parent[u]) continue;
		parent[v] = u;
		depth[v] = depth[u] + 1;
		dfs(v);
		ft[u] = ft[v];
	}
}
int lca(int u, int v)
{
	//how far up does v go before u
	if (insubt(v, u)) return -1;
	FORD(i, 20, 0)
	{
		if (!insubt(ancestor[i][v], u))
		{
			v = ancestor[i][v];
		}
	}
	return v;
}
void work(int u)
{
	if (vis[u]) return;
	vis[u] = true;
	for (pii p : edge1[u])
	{
		if (ans[p.se] != 0 && ans[p.se] != V - 1) continue;
		ans[p.se] = p.fi;
		work(p.fi);
	}
}

int32_t main()
{
	ios_base::sync_with_stdio(0); cin.tie(0);
	// cout << fixed << setprecision(10);
	// cerr << fixed << setprecision(10);
	// if (fopen("file.in", "r"))
	// {
	// 	freopen ("file.in", "r", stdin);
	// 	freopen ("file.out", "w", stdout);
	// }
	cin >> N;
	FOR(i, 0, N - 1)
	{
		int u, v; cin >> u >> v; u--; v--;
		edge[u].PB(v);
		edge[v].PB(u);
	}
	parent[0] = N; dfs(0);
	FOR(i, 0, 22)
	{
		ancestor[i][N] = N;
	}
	FOR(i, 0, N)
	{
		ancestor[0][i] = parent[i];
		dup[0][i] = {-INF, INF};
	}
	FOR(i, 1, 21)
	{
		FOR(j, 0, N)
		{
			ancestor[i][j] = ancestor[i - 1][ancestor[i - 1][j]];
			dup[i][j] = {-INF, INF};
		}
	}
	cin >> K;
	while(K--)
	{
		int u, v, val;
		char typ;
		cin >> typ >> u >> v >> val; u--; v--;
		if (typ == 'm')
		{
			int w = lca(u, v), diff = depth[v] - depth[w] + 1;
			if (w != -1)
			{
				int x = v;
				FORD(i, 20, 0)
				{
					if (diff & (1 << i))
					{
						ckmax(dup[i][x].fi, val);
						x = ancestor[i][x];
					}
				}
			}
			w = lca(v, u);
			if (w != -1)
			{
				int x = u, diff = depth[u] - depth[w] + 1;
				FORD(i, 20, 0)
				{
					if (diff & (1 << i))
					{
						ckmax(dup[i][x].fi, val);
						x = ancestor[i][x];
					}
				}
			}
		}
		if (typ == 'M')
		{
			int w = lca(u, v);
			if (w != -1)
			{
				int x = v, diff = depth[v] - depth[w] + 1;
				FORD(i, 20, 0)
				{
					if (diff & (1 << i))
					{
						ckmin(dup[i][x].se, val);
						x = ancestor[i][x];
					}
				}
			}
			w = lca(v, u);
			if (w != -1)
			{
				int x = u, diff = depth[u] - depth[w] + 1;
				FORD(i, 20, 0)
				{
					if (diff & (1 << i))
					{
						ckmin(dup[i][x].se, val);
						x = ancestor[i][x];
					}
				}
			}
		}
	}
	FORD(i, 20, 1)
	{
		FOR(j, 0, N)
		{
			ckmin(dup[i - 1][j].se, dup[i][j].se);
			ckmin(dup[i - 1][ancestor[i - 1][j]].se, dup[i][j].se);
			ckmax(dup[i - 1][j].fi, dup[i][j].fi);
			ckmax(dup[i - 1][ancestor[i - 1][j]].fi, dup[i][j].fi);
		}
	}
	FOR(i, 0, N)
	{
		bound[i] = dup[0][i];
		// cerr << bound[i].fi << ' ' << bound[i].se << endl;
	}
	vi compress;
	//you can have one or the other, but not both!
	FOR(i, 1, N)
	{
		compress.PB(bound[i].fi);
		compress.PB(bound[i].se);
	}
	compress.PB(-INF); compress.PB(INF);
	sort(ALL(compress));
	compress.erase(unique(ALL(compress)), compress.end());
	V = SZ(compress);
	FOR(i, 1, N)
	{
		bound[i].fi = LB(ALL(compress), bound[i].fi) - compress.begin();
		bound[i].se = LB(ALL(compress), bound[i].se) - compress.begin();
		if (bound[i] == MP(0, V - 1)) continue;
		edge1[bound[i].fi].PB({bound[i].se, i});
		edge1[bound[i].se].PB({bound[i].fi, i});
	}
	work(0);
	work(V - 1);
	FOR(i, 1, V - 1)
	{
		if (vis[i]) continue;
		for (pii p : edge1[i]) assert(!vis[p.fi]);
		pii p = edge1[i][0];
		ans[p.se] = i;
		// cerr << "ans" << p.se << " = " << i << endl;
		work(i);
	}
	FOR(i, 1, N)
	{
		VIS[ans[i]] = true;
	}
	FOR(i, 1, V - 1)
	{
		if (!VIS[i]) return 0;
	}
	FOR(i, 1, N)
	{
		cout << i + 1 << ' ' << parent[i] + 1 << ' ' << (ans[i] == 0 ? randomize(INF) : compress[ans[i]]) << '\n';
	}
	//we don't need to worry about 0 and V-1, but other ones we must satisfy
	// cerr << "time elapsed = " << (clock() / (CLOCKS_PER_SEC / 1000)) << " ms" << endl;
	return 0;
}
/* READ READ READ
* int overflow, maxn too small, special cases (n=1?, two distinct?), cin.tie() interactive
* reread the problem, try small cases
* note down possible sources of error as you go
* do smth instead of nothing
*/

Compilation message

minmaxtree.cpp: In function 'int32_t main()':
minmaxtree.cpp:249:48: warning: array subscript is below array bounds [-Warray-bounds]
    int w = lca(u, v), diff = depth[v] - depth[w] + 1;
                                         ~~~~~~~^

Subtask #1
7.0 / 7.0

# 결과 실행 시간 메모리 Grader output
1 Correct 24 ms 24184 KB Output is correct
2 Correct 24 ms 24188 KB Output is correct
3 Correct 25 ms 24184 KB Output is correct
4 Correct 24 ms 24184 KB Output is correct

Subtask #2
22.0 / 22.0

# 결과 실행 시간 메모리 Grader output
1 Correct 330 ms 52024 KB Output is correct
2 Correct 193 ms 50464 KB Output is correct
3 Correct 194 ms 51052 KB Output is correct
4 Correct 319 ms 52376 KB Output is correct
5 Correct 324 ms 51000 KB Output is correct
6 Correct 245 ms 50920 KB Output is correct
7 Correct 187 ms 50412 KB Output is correct

Subtask #3
0 / 29.0

# 결과 실행 시간 메모리 Grader output
1 Correct 137 ms 48620 KB Output is correct
2 Correct 138 ms 49008 KB Output is correct
3 Correct 170 ms 50000 KB Output is correct
4 Correct 191 ms 50668 KB Output is correct
5 Correct 159 ms 49004 KB Output is correct
6 Correct 158 ms 49384 KB Output is correct
7 Runtime error 171 ms 94960 KB Execution killed with signal 11 (could be triggered by violating memory limits)
8 Halted 0 ms 0 KB -

Subtask #4
0 / 42.0

# 결과 실행 시간 메모리 Grader output
1 Correct 24 ms 24184 KB Output is correct
2 Correct 24 ms 24188 KB Output is correct
3 Correct 25 ms 24184 KB Output is correct
4 Correct 24 ms 24184 KB Output is correct
5 Correct 330 ms 52024 KB Output is correct
6 Correct 193 ms 50464 KB Output is correct
7 Correct 194 ms 51052 KB Output is correct
8 Correct 319 ms 52376 KB Output is correct
9 Correct 324 ms 51000 KB Output is correct
10 Correct 245 ms 50920 KB Output is correct
11 Correct 187 ms 50412 KB Output is correct
12 Correct 137 ms 48620 KB Output is correct
13 Correct 138 ms 49008 KB Output is correct
14 Correct 170 ms 50000 KB Output is correct
15 Correct 191 ms 50668 KB Output is correct
16 Correct 159 ms 49004 KB Output is correct
17 Correct 158 ms 49384 KB Output is correct
18 Runtime error 171 ms 94960 KB Execution killed with signal 11 (could be triggered by violating memory limits)
19 Halted 0 ms 0 KB -