Submission #923769

#TimeUsernameProblemLanguageResultExecution timeMemory
923769KarootFeast (NOI19_feast)C++17
71 / 100
993 ms134996 KiB
#pragma GCC optimize("Ofast,inline") #pragma GCC optimize ("unroll-loops") #include <iostream> #include <cmath> #include <unordered_map> #include <map> #include <set> #include <queue> #include <vector> #include <string> #include <iomanip> #include <algorithm> #include <chrono> #define all(x) (x).begin(), (x).end() #define rall(x) (x).rbegin(), (x).rend() using namespace std; typedef long long ll; ll linf = 1e15+1; inline void scoobydoobydoo(){ ios::sync_with_stdio(false); ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); } const int MAXN = 3e5+3; ll arr[MAXN]; pair<long double, ll> mem[MAXN][2]; ll n, k; bool isVisited[MAXN][2]; long double lambda; pair<long double, ll> dp(ll index, int inInterval){ if (index == n) return {0, 0}; if (isVisited[index][inInterval])return mem[index][inInterval]; isVisited[index][inInterval] = true; return mem[index][inInterval] = (inInterval ? max(make_pair(dp(index+1, 1).first+arr[index], dp(index+1, 1).second), make_pair(dp(index+1, 0).first, dp(index+1, 0).second)) : max(make_pair(dp(index+1, 0).first, dp(index+1, 0).second), make_pair(dp(index+1, 1).first + arr[index] - lambda, dp(index+1, 1).second+1))); } bool check(long double la){ lambda = la; for (int i = 0; i < n; i++){ isVisited[i][0] = false; isVisited[i][1] = false; } //cout << la << " " << dp(0, 0).first << " " << dp(0, 0).second << endl; return dp(0,0).second >= k; } int main(){ scoobydoobydoo(); cin >> n >> k; for (int i = 0; i < n; i++)cin >> arr[i]; long double b = 0; for (int i = 0; i < n; i++)b += abs(arr[i]); long double a = 0; chrono::time_point<chrono::system_clock> start, end; start = chrono::system_clock::now(); while (a+(1e-3) < b){ long double mid = (a+b)/2.0; if (check(mid)){ a = mid; } else { b = mid; } end = chrono::system_clock::now(); chrono::duration<double> elapsed_seconds = end - start; if (elapsed_seconds.count() > 0.91)break; } check(a); ll ans = round(a*k + mem[0][0].first); cout << ans << endl; return 0; }
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