Submission #923587

#	Time	Username	Problem	Language	Result	Execution time	Memory
923587		GrindMachine	Measures (CEOI22_measures)	C++17	76 / 100	638 ms	42288 KiB

Main

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

using namespace std;
using namespace __gnu_pbds;

template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
typedef long long int ll;
typedef long double ld;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;

#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL)
#define pb push_back
#define endl '\n'
#define sz(a) (int)a.size()
#define setbits(x) __builtin_popcountll(x)
#define ff first
#define ss second
#define conts continue
#define ceil2(x,y) ((x+y-1)/(y))
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define yes cout << "Yes" << endl
#define no cout << "No" << endl

#define rep(i,n) for(int i = 0; i < n; ++i)
#define rep1(i,n) for(int i = 1; i <= n; ++i)
#define rev(i,s,e) for(int i = s; i >= e; --i)
#define trav(i,a) for(auto &i : a)

template<typename T>
void amin(T &a, T b) {
    a = min(a,b);
}

template<typename T>
void amax(T &a, T b) {
    a = max(a,b);
}

#ifdef LOCAL
#include "debug.h"
#else
#define debug(x) 42
#endif

/*



*/

const int MOD = 1e9 + 7;
const int N = 1e5 + 5;
const int inf1 = int(1e9) + 5;
const ll inf2 = ll(1e18) + 5;

template<typename T>
struct lazysegtree {
    /*=======================================================*/

    struct data {
        ll mn,mx,res,active;
    };

    struct lazy {
        ll a;
    };

    data d_neutral = {inf2,-inf2,0,0};
    lazy l_neutral = {0};

    void merge(data &curr, data &left, data &right) {
        curr.mn = min(left.mn,right.mn);
        curr.mx = max(left.mx,right.mx);
        curr.res = max({left.res,right.res,left.mx-right.mn});
        curr.active = left.active+right.active;
    }

    void create(int x, int lx, int rx, T v) {

    }

    void modify(int x, int lx, int rx, T v) {
        if(v.ff == 1){
            lz[x].a = v.ss;
        }
        else{
            tr[x].mn = tr[x].mx = v.ss;
            tr[x].res = 0;
            tr[x].active = 1;
        }
    }

    void propagate(int x, int lx, int rx) {
        ll v = lz[x].a;
        if(!v) return;

        tr[x].mn += v;
        tr[x].mx += v;

        if(rx-lx > 1){
            lz[2*x+1].a += v;
            lz[2*x+2].a += v;
        }

        lz[x] = l_neutral;
    }

    /*=======================================================*/

    int siz = 1;
    vector<data> tr;
    vector<lazy> lz;

    lazysegtree() {

    }

    lazysegtree(int n) {
        while (siz < n) siz *= 2;
        tr.assign(2 * siz, d_neutral);
        lz.assign(2 * siz, l_neutral);
    }

    void build(vector<T> &a, int n, int x, int lx, int rx) {
        if (rx - lx == 1) {
            if (lx < n) {
                create(x, lx, rx, a[lx]);
            }

            return;
        }

        int mid = (lx + rx) / 2;

        build(a, n, 2 * x + 1, lx, mid);
        build(a, n, 2 * x + 2, mid, rx);

        merge(tr[x], tr[2 * x + 1], tr[2 * x + 2]);
    }

    void build(vector<T> &a, int n) {
        build(a, n, 0, 0, siz);
    }

    void rupd(int l, int r, T v, int x, int lx, int rx) {
        propagate(x, lx, rx);

        if (lx >= r or rx <= l) return;
        if (lx >= l and rx <= r) {
            modify(x, lx, rx, v);
            propagate(x, lx, rx);
            return;
        }

        int mid = (lx + rx) / 2;

        rupd(l, r, v, 2 * x + 1, lx, mid);
        rupd(l, r, v, 2 * x + 2, mid, rx);

        merge(tr[x], tr[2 * x + 1], tr[2 * x + 2]);
    }

    void rupd(int l, int r, T v) {
        rupd(l, r + 1, v, 0, 0, siz);
    }

    data query(int l, int r, int x, int lx, int rx) {
        propagate(x, lx, rx);

        if (lx >= r or rx <= l) return d_neutral;
        if (lx >= l and rx <= r) return tr[x];

        int mid = (lx + rx) / 2;

        data curr;
        data left = query(l, r, 2 * x + 1, lx, mid);
        data right = query(l, r, 2 * x + 2, mid, rx);

        merge(curr, left, right);
        return curr;
    }

    data query(int l, int r) {
        return query(l, r + 1, 0, 0, siz);
    }
};

void solve(int test_case)
{
    ll n,m,d; cin >> n >> m >> d;
    d *= 2;
    vector<ll> a(n+5), b(m+5);
    rep1(i,n) cin >> a[i], a[i] *= 2;
    rep1(i,m) cin >> b[i], b[i] *= 2;

    vector<ll> c;
    rep1(i,n) c.pb(a[i]);
    rep1(i,m) c.pb(b[i]);
    c.pb(0);

    sort(all(c));
    ll siz = sz(c)-1;
    map<ll,ll> mp;

    rep1(i,siz){
        if(c[i] != c[i-1]){
            mp[c[i]] = i;
        }
    }

    lazysegtree<pll> st(siz+5);

    auto upd = [&](ll x){
        ll i = mp[x]++;
        st.rupd(i+1,siz,{1,-d});
        ll active = st.query(1,i-1).active;
        st.rupd(i,i,{2,x-d*(active+1)});
    };

    rep1(i,m){
        ll x = b[i];
        upd(x);
        ll ans = st.query(1,siz).res;
        ans /= 2;
        cout << ans/2;
        if(ans&1) cout << ".5";
        cout << " ";   
    }

    cout << endl;
}

int main()
{
    fastio;

    int t = 1;
    // cin >> t;

    rep1(i, t) {
        solve(i);
    }

    return 0;
}

• Subtask 1: 0 / 10
• Subtask 2: 0 / 14
• Subtask 3: 35 / 35
• Subtask 4: 41 / 41