제출 #916059

#제출 시각아이디문제언어결과실행 시간메모리
916059GrindMachineGap (APIO16_gap)C++17
8.65 / 100
404 ms3176 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) (int)a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x,y) ((x+y-1)/(y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i,n) for(int i = 0; i < n; ++i) #define rep1(i,n) for(int i = 1; i <= n; ++i) #define rev(i,s,e) for(int i = s; i >= e; --i) #define trav(i,a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a,b); } template<typename T> void amax(T &a, T b) { a = max(a,b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* read some solutions a long time ago, slightly remember some ideas may have still solved it if not for those ideas */ const int MOD = 1e9 + 7; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; const int B = 75; #include "gap.h" ll go(ll l, ll r){ if(l >= r) return 0; // split into B segs ll len = r-l+1; ll cnt1 = B; ll cnt2 = len%B; cnt1 -= cnt2; vector<pll> segs; ll ptr = l; rep1(i,cnt1){ if(len >= B){ segs.pb({ptr,ptr+len/B-1}); } ptr += len/B; } rep1(i,cnt2){ segs.pb({ptr,ptr+ceil2(len,B)-1}); ptr += ceil2(len,B); } // cout << "l = " << l << endl; // cout << "r = " << r << endl; // for(auto [lx,rx] : segs){ // cout << lx << " " << rx << endl; // } assert(ptr == r+1); vector<pll> seg_vals; ll ans = 0; rep(i,sz(segs)){ ll mn,mx; auto [lx,rx] = segs[i]; MinMax(lx,rx,&mn,&mx); seg_vals.pb({mn,mx}); if(mn != mx){ amax(ans,go(lx,rx)); } } ll last_active = -1; for(auto [mn,mx] : seg_vals){ if(mn != -1){ if(last_active != -1){ amax(ans,mn-last_active); } last_active = mx; } } return ans; } long long findGap(int T, int n) { return go(0,inf2); }
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