이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
typedef long long int ll;
typedef long double ld;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL)
#define pb push_back
#define endl '\n'
#define sz(a) (int)a.size()
#define setbits(x) __builtin_popcountll(x)
#define ff first
#define ss second
#define conts continue
#define ceil2(x,y) ((x+y-1)/(y))
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define yes cout << "Yes" << endl
#define no cout << "No" << endl
#define rep(i,n) for(int i = 0; i < n; ++i)
#define rep1(i,n) for(int i = 1; i <= n; ++i)
#define rev(i,s,e) for(int i = s; i >= e; --i)
#define trav(i,a) for(auto &i : a)
template<typename T>
void amin(T &a, T b) {
a = min(a,b);
}
template<typename T>
void amax(T &a, T b) {
a = max(a,b);
}
#ifdef LOCAL
#include "debug.h"
#else
#define debug(x) 42
#endif
/*
*/
const int MOD = 1e9 + 7;
const int N = 2e5 + 5;
const int inf1 = int(1e9) + 5;
const ll inf2 = ll(1e18) + 5;
vector<pll> adj[N];
vector<ll> dp[N];
void dfs(ll u, ll p){
for(auto [v,w] : adj[u]){
if(v == p) conts;
dfs(v,u);
}
dp[u] = vector<ll>(sz(adj[u])+1);
ll sum = 0;
rep(i,sz(adj[u])){
auto [v,w] = adj[u][i];
if(v == p) conts;
ll curr_val = -inf2;
rep(j,sz(adj[v])){
auto [v2,w2] = adj[v][j];
if(v2 == u) conts;
ll val = w+w2+dp[v2][0]+dp[v][j+1];
amax(curr_val,val);
}
amax(curr_val,dp[v][0]);
dp[u][i+1] = -curr_val;
sum += curr_val;
}
rep(i,sz(adj[u])+1){
dp[u][i] += sum;
}
}
void solve(int test_case)
{
ll n; cin >> n;
rep1(i,n-1){
ll u,v,c; cin >> u >> v >> c;
adj[u].pb({v,c}), adj[v].pb({u,c});
}
ll ans = -inf2;
rep1(i,n){
dfs(i,-1);
amax(ans,dp[i][0]);
}
cout << ans << endl;
}
int main()
{
fastio;
int t = 1;
// cin >> t;
rep1(i, t) {
solve(i);
}
return 0;
}
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