제출 #90500

#제출 시각아이디문제언어결과실행 시간메모리
90500jasony123123Kosta (COI14_kosta)C++11
20 / 100
42 ms11588 KiB
#define _CRT_SECURE_NO_WARNINGS #include <bits/stdc++.h> //#include <ext/pb_ds/tree_policy.hpp> //#include <ext/pb_ds/assoc_container.hpp> using namespace std; //using namespace __gnu_pbds; #define FOR(i,start,end) for(int i=start;i<(int)(end);i++) #define FORE(i,start,end) for(int i=start;i<=(int)end;i++) #define RFOR(i,start,end) for(int i = start; i>end; i--) #define RFORE(i,start,end) for(int i = start; i>=end; i--) #define all(a) a.begin(), a.end() #define mt make_tuple #define mp make_pair #define v vector #define sf scanf #define pf printf #define dvar(x) cout << #x << " := " << x << "\n" #define darr(x,n) FOR(i,0,n) cout << #x << "[" << i << "]" << " := " << x[i] << "\n" typedef long long ll; typedef long double ld; typedef pair<int, int > pii; typedef pair<ll, ll> pll; //template <class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; template<class T> void minn(T &a, T b) { a = min(a, b); } template<class T> void maxx(T &a, T b) { a = max(a, b); } void io() { #ifdef LOCAL_PROJECT freopen("input.in", "r", stdin); freopen("output.out", "w", stdout); #else /* online submission */ #endif ios_base::sync_with_stdio(false); cin.tie(NULL); } const ll MOD = 1000000007LL; const ll PRIME = 105943LL; const int INF = 1e8; /****************************************************************/ /* Find minimum D st K points with boxes of 2D sides cover all points */ struct BBox { int x1, y1, x2, y2; BBox() { x1 = INF, y1 = INF, x2 = -INF, y2 = -INF; } void upd(pii a) { minn(x1, a.first); maxx(x2, a.first); minn(y1, a.second); maxx(y2, a.second); } }; const int MAXN = 200000; int K, N; pii pnts[MAXN]; void solve1() { BBox b; FOR(i, 0, N) b.upd(pnts[i]); pii ans = { INF, -1 }; FOR(i, 0, N) { int d = max(max(abs(b.x1 - pnts[i].first), abs(b.x2 - pnts[i].first)), max(abs(b.y1 - pnts[i].second), abs(b.y2 - pnts[i].second))); minn(ans, { d,i }); } cout << ans.first << "\n" << ans.second + 1 << "\n"; } void solve2() { cout << "Lol"; } int main() { io(); cin >> K >> N; FOR(i, 0, N) { int x, y; cin >> x >> y; pnts[i].first = x + y; pnts[i].second = x - y; } if (K == 1) solve1(); else solve2(); return 0; }
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