Submission #897634

#TimeUsernameProblemLanguageResultExecution timeMemory
897634GrindMachineA Difficult(y) Choice (BOI21_books)C++17
100 / 100
1 ms856 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) (int)a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x,y) ((x+y-1)/(y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i,n) for(int i = 0; i < n; ++i) #define rep1(i,n) for(int i = 1; i <= n; ++i) #define rev(i,s,e) for(int i = s; i >= e; --i) #define trav(i,a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a,b); } template<typename T> void amax(T &a, T b) { a = max(a,b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* read the sol a long time ago and remember some ideas from there */ const int MOD = 1e9 + 7; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; #include "books.h" void solve(int n, int k, long long A, int S) { map<ll,ll> mp; auto my_skim = [&](ll i){ if(mp.count(i)) return mp[i]; else return mp[i] = skim(i); }; ll first_big = n+1; ll l = 1, r = n; while(l <= r){ ll mid = (l+r) >> 1; ll val = my_skim(mid); if(val >= A){ first_big = mid; r = mid-1; } else{ l = mid+1; } } vector<ll> a(k+5); rep1(i,k){ a[i] = my_skim(i); } if(first_big <= n){ ll sum = my_skim(first_big); rep1(i,k-1) sum += a[i]; if(sum >= A and sum <= 2*A){ vector<int> ans; rep1(i,k-1) ans.pb(i); ans.pb(first_big); answer(ans); return; } } ll sum = 0; rep1(i,k) sum += a[i]; if(sum > 2*A){ impossible(); return; } deque<int> dq; rep1(i,k) dq.pb(i); if(sum >= A){ vector<int> ans(all(dq)); answer(ans); return; } ll ptr = first_big-1; rev(i,k,1){ sum -= a[i]; sum += my_skim(ptr); dq.pop_back(); dq.push_front(ptr); ptr--; if(sum >= A){ assert(sum <= 2*A); vector<int> ans(all(dq)); answer(ans); return; } } impossible(); }
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