제출 #890591

#제출 시각아이디문제언어결과실행 시간메모리
890591hafoCollecting Stamps 3 (JOI20_ho_t3)C++14
100 / 100
108 ms267388 KiB
#include <bits/stdc++.h> #define ll long long #define ull unsigned ll #define pb push_back #define pa pair<int, int> #define pall pair<ll, int> #define fi first #define se second #define TASK "test" #define Size(x) (int) x.size() #define all(x) x.begin(), x.end() using namespace std; template<typename T1, typename T2> bool mini (T1 &a, T2 b) {if(a > b) a = b; else return 0; return 1;} template<typename T1, typename T2> bool maxi (T1 &a, T2 b) {if(a < b) a = b; else return 0; return 1;} const int MOD = 1e9 + 7; const int LOG = 20; const int maxn = 4e2 + 7; const ll oo = 1e9 + 69; int n, l, x[maxn], t[maxn], dp[maxn][maxn][207][2]; int add(int a, int b) { a += b; if(a >= l) a -= l; if(a < 0) a += l; return a; } int dist(int a, int b) { return min(add(b, -a), add(a, -b)); } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); //freopen(TASK".inp", "r", stdin); //freopen(TASK".out", "w", stdout); cin>>n>>l; for(int i = 1; i <= n; i++) { cin>>x[i]; x[i + n + 1] = x[i]; } for(int i = 1; i <= n; i++) { cin>>t[i]; t[i + n + 1] = t[i]; } x[1 + n] = 0; t[1 + n] = 0; int ans = 0; for(int i = 0; i <= n * 2 + 1; i++) { for(int j = 0; j <= n * 2 + 1; j++) { for(int k = 0; k <= n; k++) { for(int t = 0; t < 2; t++) dp[i][j][k][t] = oo; } } } dp[n + 1][n + 1][0][0] = 0; dp[n + 1][n + 1][0][1] = 0; for(int i = 2 * n + 1; i >= 1; i--) { for(int j = i; j <= 2 * n + 1; j++) { if(j - i + 1 >= n + 1 || i > n + 1 || j < n + 1) continue; for(int k = 0; k <= n; k++) { mini(dp[i][j][k][1], dp[i][j][k][0] + dist(x[j], x[i])); mini(dp[i][j][k][0], dp[i][j][k][1] + dist(x[i], x[j])); int nxt = dp[i][j][k][0]; if(i - 1 >= 1) { nxt += dist(x[i - 1], x[i]); if(nxt <= t[i - 1] && k + 1 <= n) { mini(dp[i - 1][j][k + 1][0], nxt); maxi(ans, k + 1); } else mini(dp[i - 1][j][k][0], nxt); } nxt = dp[i][j][k][1]; if(j + 1 <= 2 * n + 1) { nxt += dist(x[j + 1], x[j]); if(nxt <= t[j + 1] && k + 1 <= n) { mini(dp[i][j + 1][k + 1][1], nxt); maxi(ans, k + 1); } else mini(dp[i][j + 1][k][1], nxt); } } } } cout<<ans; return 0; }
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