이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
//#include "friend.h"
using namespace std;
#define f first
#define s second
vector<int> adjlist[1001];
int types[1001];
void st5dfs(int node, int type) {
if (types[node] != -1) return; // if go back to parent
types[node] = type;
for (int idx=0; idx<(int)adjlist[node].size(); idx++) {
st5dfs( adjlist[node][idx] , 1-type ); // push neighbours to other colour
}
}
int findSample(int n, int confidence[], int host[], int protocol[]) {
// st5: bipartite graphs
// prep adjlist
for (int guest=1; guest<n; guest++) {
if (protocol[guest] == 0) { // i am your friend
adjlist[host[guest]].push_back(guest);
adjlist[guest].push_back(host[guest]);
} else if (protocol[guest] == 1) { // your friends are my friends
for (int idx=0; idx<(int)adjlist[host[guest]].size(); idx++) {
int person = adjlist[host[guest]][idx];
adjlist[person].push_back(guest);
adjlist[guest].push_back(person);
}
}
}
// dfs each one
bool completed[n];
int res = 0, t0, t1;
for (int i=0; i<n; i++) {
if (completed[i]) continue;
// prep types
for (int j=0; j<n; j++) types[j] = -1;
st5dfs(i, 0); // arbritrary 0
t0=0; t1=0;
for (int j=0; j<n; j++) {
if (types[j] == -1) continue;
completed[j] = true;
if (types[j] == 0) t0++;
else t1++;
}
res += max(t0, t1);
}
return res;
}
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