이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
vector <int> ans,col[300001],ve;
vector <pair <int, int>> ke[300001];
int n,m,p[300001],d[300001],r[300001],isleaf[300001],sum;
int f(int i){
return (p[i]==i?i:p[i]=f(p[i]));
}
void unite(int i, int j){
p[f(j)]=f(i);
}
int bfs(int s){
queue <int> q;
q.push(s);
d[s]=1;
int res=-1;
ve.clear();
while (!q.empty()){
int u=q.front();
q.pop();
if (f(u)!=f(s)){
res=u;
break;
}
ve.push_back(u);
for (auto [v,c]:ke[u])
if (!d[v])
col[c].push_back(v);
for (int v:col[r[u]])
if (!d[v]){
d[v]=1;
q.push(v);
}
col[r[u]].clear();
}
for (int i:ve){
d[i]=0;
for (auto [v,c]:ke[i])
col[c].clear();
}
d[res]=0;
sum+=ve.size();
return res;
}
vector <int> find_reachable(vector <int> R, vector <int> u, vector <int> v, vector <int> c){
n=R.size();
m=u.size();
for (int i=0;i<n;i++){
r[i]=R[i];
p[i]=i;
ans.push_back(0);
}
for (int i=0;i<m;i++){
ke[u[i]].push_back({v[i],c[i]});
ke[v[i]].push_back({u[i],c[i]});
}
bool ch=true;
vector <pair <int, int>> tmp;
while (ch){
ch=false;
tmp.clear();
for (int i=0;i<n;i++)
if (f(i)==i&&!isleaf[i]){
int j=bfs(i);
if (j==-1)
isleaf[i]=1;
else{
tmp.push_back({j,i});
ch=true;
}
}
for (auto [u,v]:tmp)
unite(u,v);
}
int mn=1e9;
for (int i=0;i<n;i++){
if (i==f(i)){
bfs(i);
mn=min(mn,(int)ve.size());
}
}
for (int i=0;i<n;i++)
if (i==f(i)){
bfs(i);
if (ve.size()==mn)
for (int j:ve)
ans[j]=1;
}
return ans;
}
컴파일 시 표준 에러 (stderr) 메시지
keys.cpp: In function 'std::vector<int> find_reachable(std::vector<int>, std::vector<int>, std::vector<int>, std::vector<int>)':
keys.cpp:85:26: warning: comparison of integer expressions of different signedness: 'std::vector<int>::size_type' {aka 'long unsigned int'} and 'int' [-Wsign-compare]
85 | if (ve.size()==mn)
| ~~~~~~~~~^~~~
keys.cpp:82:5: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
82 | for (int i=0;i<n;i++)
| ^~~
keys.cpp:89:2: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
89 | return ans;
| ^~~~~~
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