제출 #861881

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
861881		sleepntsheep	Two Currencies (JOI23_currencies)	C++17	0 / 100	2 ms	12636 KiB

currencies

#include <cstdio>
#include <cstring>
#include <cassert>
#include <string>
#include <deque>
#include <vector>
#include <map>
#include <queue>
#include <algorithm>
#include <iostream>
#include <utility>
using namespace std;
using ll = long long;
using ld = long double;
#define ShinLena cin.tie(nullptr)->sync_with_stdio(false)


#define N 100005
#define ALL(x) x.begin(), x.end()

struct persist
{
    int a; ll b;
    persist *l, *r;
    persist(int a0, ll b0) : a(a0), b(b0), l(nullptr), r(nullptr) {}
    persist(persist *l0, persist *r0) : a((l0?l0->a:0) + (r0?r0->a:0)), 
        b((l0?l0->b:0) + (r0?r0->b:0)), l(l0), r(r0) {}
    ~persist() {if (l) delete l; if (r) delete r;}
};

persist *build(int l, int r)
{
    if (l == r) return new persist(0, 0);
    return new persist(build(l, (l+r)/2), build((l+r)/2+1, r));
}

persist *upd(persist *v, int l, int r, int w, int W)
{
    if (l == r) return new persist(v->a + 1, v->b + w);
    if (W <= (l+r)/2) return new persist(upd(v->l, l, (l+r)/2, w, W), v->r);
    return new persist(v->l, upd(v->r, (l+r)/2+1, r, w, W));
}

vector<int> silver_cord;

ll qry(persist *u, persist *v, persist *a, int l, int r, ll k)
{
    if (l == r)
    {
        if (l >= (int)silver_cord.size()) return 0;
        return k / silver_cord[l];
    }
    ll left = u->l->b + v->l->b - a->l->b * 2;
    if (k <= left) return qry(u->l, v->l, a->l, l, (l+r)/2, k);
    return (u->l->a + v->l->a - a->l->a * 2) +
        qry(u->r, v->r, a->r, (l+r)/2+1, r, k - left);
}

ll qry_count(persist *u, persist *v, persist *a)
{
    return u->a + v->a - a->a * 2;
}

int n, m, q, P[17][N], dep[N];
vector<int> mark[N];
vector<tuple<int, int>> g[N];
persist *root[N];

int lca(int u, int v)
{
    if (dep[u] < dep[v]) swap(v, u);
    int dt = dep[u] - dep[v];
    for (int j = 17; j--;) if (dt & (1 << j)) u = P[j][u];
    if (u == v) return u;
    for (int j = 17; j--;) if (P[j][u] != P[j][v]) u = P[j][u], v = P[j][v];
    return P[0][u];
}

void dfs(int u, int p, int d)
{
    dep[u] = d; P[0][u] = p; for (int j = 1; j < 17; ++j) P[j][u] = P[j-1][P[j-1][u]];
    for (auto [v, i] : g[u]) 
    {
        if (v == p) continue;
        root[v] = root[u];
        for (auto w : mark[i]) root[v] = upd(root[v], 0, n, w, lower_bound(ALL(silver_cord), w) - silver_cord.begin());
        dfs(v, u, d+1);
    }
}

int main()
{
    ShinLena;
    cin >> n >> m >> q;
    for (int u, v, i = 1; i < n; ++i) cin >> u >> v, g[u].emplace_back(v, i), g[v].emplace_back(u, i);
    for (int i = 0, p, c; i < m; ++i) cin >> p >> c, mark[p].push_back(c), silver_cord.push_back(c);

    sort(ALL(silver_cord)); silver_cord.erase(unique(ALL(silver_cord)), silver_cord.end());

    root[1] = build(0, n); dfs(1, 1, 1);

    for (ll s, t, a, gold, silver, i = 0; i < q; ++i)
    {
        cin >> s >> t >> gold >> silver;
        a = lca(s, t);
        persist *ps = root[s], *pt = root[t], *pa = root[a];
        int gone = qry(ps, pt, pa, 0, n, silver), all = qry_count(ps, pt, pa);

        cout << ((all - gone > gold) ? -1 : all - gone) << '\n';
    }

    return 0;
}

• Subtask 1: 0 / 10
• Subtask 2: 0 / 28
• Subtask 3: 0 / 30
• Subtask 4: 0 / 32