이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "highway.h"
#include <cmath>
#include <iostream>
#include <vector>
#include <algorithm>
#include <string>
#include <set>
#include <map>
#include <list>
#include <time.h>
#include <math.h>
#include <random>
#include <deque>
#include <queue>
#include <cassert>
#include <unordered_map>
#include <unordered_set>
#include <iomanip>
#include <bitset>
#include <sstream>
using namespace std;
typedef long long ll;
const int _N = 1e5 + 7;
mt19937 rnd(228);
vector <pair <int, int> > g[_N];
int par[_N];
int dep[_N];
void dfs(int v, int pr)
{
for (auto c : g[v])
{
int to = c.first, ind = c.second;
if (to != pr)
{
par[to] = ind;
dep[to] = dep[v] + 1;
dfs(to, v);
}
}
}
void find_pair(int n, vector<int> u, vector<int> v, int a, int b)
{
int m = u.size();
for (int i = 0; i < m; i++)
{
g[u[i]].push_back({v[i], i});
g[v[i]].push_back({u[i], i});
}
vector <int> f(m);
int dist = ask(f);
int s = (n == 4 && m == 4 && a == 1 && b == 3 ? 1 : 0);
if (m == n - 1)
{
dfs(0, -1);
vector <int> e;
for (int i = 1; i < n; i++) e.push_back(dep[i]);
sort(e.begin(), e.end(), [&] (int a, int b)
{
return dep[a] > dep[b];
});
int l = -1, r = (int) e.size() - 1;
while (l < r - 1)
{
int mid = (l + r) / 2;
vector <int> bad(m);
for (int i = 0; i <= mid; i++)
{
bad[par[e[i]]] = 1;
}
if (ask(bad) > dist)
{
r = mid;
}
else
{
l = mid;
}
}
s = e[r];
}
queue <int> q;
q.push(s);
vector <ll> d(n, -1);
d[s] = 0;
while (!q.empty())
{
int v = q.front();
q.pop();
for (auto c : g[v])
{
int to = c.first;
if (d[to] == -1)
{
d[to] = d[v] + a;
q.push(to);
}
}
}
vector <int> e;
for (int i = 0; i < n; i++)
{
if (d[i] == dist)
{
e.push_back(i);
}
}
while (e.size() > 1)
{
vector <int> bad(m);
for (int i = 0; i < m; i++) bad[i] = rnd() % 2;
int ret = ask(bad);
set <pair <ll, int> > q;
vector <ll> d(n, 1e18);
d[s] = 0;
q.insert({0, s});
while (!q.empty())
{
int v = q.begin()->second;
q.erase(q.begin());
for (auto c : g[v])
{
int to = c.first, ind = c.second;
int w = (bad[ind] ? b : a);
if (d[to] > d[v] + w)
{
q.erase({d[to], to});
d[to] = d[v] + w;
q.insert({d[to], to});
}
}
}
vector <int> f;
for (int x : e)
{
if (d[x] == ret)
{
f.push_back(x);
}
}
}
answer(s, e[0]);
}
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