oj.uz

답안 #843466

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
843466 2023-09-04T03:09:56 Z daoquanglinh2007 공장들 (JOI14_factories) C++17
15 / 100
 8000 ms 152980 KB 
#include "factories.h"
#include <bits/stdc++.h>
#define taskname ""
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define ll long long
#define ld long double
#define pb push_back
#define ff first
#define ss second
#define pii pair<int, int>
#define vi vector<int>
#define vll vector<ll>
#define vvi vector<vi>
#define vii vector<pii>
#define isz(x) (int)x.size()
using namespace std;
 
const int mxN = 5e5 + 5;
const ll oo = 1e18;
 
int n;
vector<vii> G;
 
vi vtn;
vector<vii> vt;
 
ll dis[mxN];
pii sparse[19][mxN];
int timer, ecnt, ap[mxN], dep[mxN], cur[mxN], tin[mxN], tout[mxN];
 
void dfs(int v, int p) {
    tin[v] = ++timer;
    dep[v] = dep[p] + 1;
    sparse[0][++ecnt] = {dep[v], v};
    ap[v] = ecnt;
 
    for(auto &[u, w] : G[v]) {
        if(u == p) continue;
        dis[u] = dis[v] + p;
        dfs(u, v);
        sparse[0][++ecnt] = {dep[v], v};
    }
 
    tout[v] = ++timer;
}
 
void build_sparse() {
    for(int p = 1, i = 1; p << 1 <= ecnt; p <<= 1, ++i)
        for(int j = 1; j <= ecnt - (p << 1) + 1; ++j)
            sparse[i][j] = min(sparse[i - 1][j], sparse[i - 1][j + p]);
}
 
bool is_ancestor(int u, int v) {
    return tin[u] <= tin[v] && tout[u] >= tout[v];
}
 
int LCA(int u, int v) {
    int l = ap[u], r = ap[v];
    if(l > r) swap(l, r);
    int len = r - l + 1, lg_len = __lg(len);
    return min(sparse[lg_len][l], sparse[lg_len][r - (1 << lg_len) + 1]).ss;
}
 
void Init(int N, int A[], int B[], int D[]) {
    n = N;
    G.resize(n); vt.resize(n);
    for(int i = 0; i < N - 1; ++i) {
        G[A[i]].emplace_back(B[i], D[i]);
        G[B[i]].emplace_back(A[i], D[i]);
    }
    dfs(0, 0); build_sparse();
}
 
long long Query(int S, int X[], int T, int Y[]) {
    queue<pii> q;
 
    for(int i = 0; i < S; ++i) {
        cur[X[i]] = 1;
        q.emplace(X[i], 0);
        vtn.emplace_back(X[i]);
    }
    for(int i = 0; i < T; ++i) {
        cur[Y[i]] = 2;
        vtn.emplace_back(Y[i]);
    }
 
    sort(all(vtn), [&](int u, int v) {
        return tin[u] < tin[v];
    });
 
    for(int i = 0; i < S + T - 1; ++i) {
        vtn.emplace_back(LCA(vtn[i], vtn[i + 1]));
    }
 
    sort(all(vtn), [&](int u, int v) {
        return tin[u] < tin[v];
    });
    vtn.erase(unique(all(vtn)), vtn.end());
 
    auto add_vt = [&](int u, int v, int w) {
        vt[u].emplace_back(v, w);
        vt[v].emplace_back(u, w);
    };
 
    stack<int> s;
    for(int i = 0; i < isz(vtn); ++i) {
        while(not s.empty() && not is_ancestor(s.top(), vtn[i])) s.pop();
        if(s.empty()) s.emplace(vtn[i]);
        else {
            add_vt(s.top(), vtn[i], dis[vtn[i]] - dis[s.top()]);
            s.emplace(vtn[i]);
        }
    }
 
    ll res = oo;
 
    auto dfs = [&](auto self, int v, int p) -> vll {
        vll cur_dis(2, oo);
        if(cur[v]) cur_dis[cur[v] - 1] = 0;
        for(auto &[u, w] : G[v]) {
            if(u == p) continue;
            vll tmp = self(self, u, v);
            for(int i = 0; i < 2; ++i)
                cur_dis[i] = min(cur_dis[i], tmp[i] + w);
        }
        res = min(res, accumulate(all(cur_dis), 0LL));
        return cur_dis;
    };
 
    dfs(dfs, vtn[0], 0);
 
    for(int i = 0; i < S; ++i) {
        cur[X[i]] = 0;
        vt[X[i]].clear();
    }
    for(int i = 0; i < T; ++i) {
        cur[Y[i]] = 0;
        vt[Y[i]].clear();
    }
    vtn.clear();
 
    return res;
}

Subtask #1
15.0 / 15.0

# 결과 실행 시간 메모리 Grader output
1 Correct 22 ms 45908 KB Output is correct
2 Correct 1336 ms 57572 KB Output is correct
3 Correct 1504 ms 57700 KB Output is correct
4 Correct 1532 ms 57812 KB Output is correct
5 Correct 1624 ms 57172 KB Output is correct
6 Correct 812 ms 57044 KB Output is correct
7 Correct 1477 ms 57296 KB Output is correct
8 Correct 1496 ms 57712 KB Output is correct
9 Correct 1654 ms 57484 KB Output is correct
10 Correct 801 ms 56996 KB Output is correct
11 Correct 1500 ms 57360 KB Output is correct

Subtask #2
0 / 18.0

# 결과 실행 시간 메모리 Grader output
1 Correct 11 ms 45656 KB Output is correct
2 Execution timed out 8055 ms 152980 KB Time limit exceeded
3 Halted 0 ms 0 KB -

Subtask #3
0 / 67.0

# 결과 실행 시간 메모리 Grader output
1 Correct 22 ms 45908 KB Output is correct
2 Correct 1336 ms 57572 KB Output is correct
3 Correct 1504 ms 57700 KB Output is correct
4 Correct 1532 ms 57812 KB Output is correct
5 Correct 1624 ms 57172 KB Output is correct
6 Correct 812 ms 57044 KB Output is correct
7 Correct 1477 ms 57296 KB Output is correct
8 Correct 1496 ms 57712 KB Output is correct
9 Correct 1654 ms 57484 KB Output is correct
10 Correct 801 ms 56996 KB Output is correct
11 Correct 1500 ms 57360 KB Output is correct
12 Correct 11 ms 45656 KB Output is correct
13 Execution timed out 8055 ms 152980 KB Time limit exceeded
14 Halted 0 ms 0 KB -