oj.uz

답안 #843445

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
843445 2023-09-04T02:35:47 Z hotboy2703 공장들 (JOI14_factories) C++17
15 / 100
 4097 ms 57592 KB 
#include "factories.h"
#include <bits/stdc++.h>
#define taskname ""
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define ll long long
#define ld long double
#define pb push_back
#define ff first
#define ss second
#define pii pair<int, int>
#define vi vector<int>
#define vll vector<ll>
#define vvi vector<vi>
#define vii vector<pii>
#define isz(x) (int)x.size()
using namespace std;

const int mxN = 5e5 + 5;
const ll oo = 1e18;

int n;
vector<vii> G;

vi vtn;
//vii -> vll
vector<vector <pair <int,ll> > > vt;

ll dis[mxN];
pii sparse[19][mxN];
int timer, ecnt, ap[mxN], dep[mxN], cur[mxN], tin[mxN], tout[mxN];

void dfs(int v, int p) {
    tin[v] = ++timer;
    dep[v] = dep[p] + 1;
    sparse[0][++ecnt] = {dep[v], v};
    ap[v] = ecnt;
    //dis
    for(auto &[u, w] : G[v]) {
        if(u == p) continue;
        dis[u] = dis[v] + w;
        dfs(u, v);
        sparse[0][++ecnt] = {dep[v], v};
    }

    tout[v] = ++timer;
}

void build_sparse() {
    for(int p = 1, i = 1; p << 1 <= ecnt; p <<= 1, ++i)
        for(int j = 1; j <= ecnt - (p << 1) + 1; ++j)
            sparse[i][j] = min(sparse[i - 1][j], sparse[i - 1][j + p]);
}

bool is_ancestor(int u, int v) {
    return tin[u] <= tin[v] && tout[u] >= tout[v];
}

int LCA(int u, int v) {
    int l = ap[u], r = ap[v];
    if(l > r) swap(l, r);
    int len = r - l + 1, lg_len = __lg(len);
    return min(sparse[lg_len][l], sparse[lg_len][r - (1 << lg_len) + 1]).ss;
}

void Init(int N, int A[], int B[], int D[]) {
    n = N;
    G.resize(n); vt.resize(n);
    for(int i = 0; i < N - 1; ++i) {
        G[A[i]].emplace_back(B[i], D[i]);
        G[B[i]].emplace_back(A[i], D[i]);
    }
    dfs(0, 0); build_sparse();
}

long long Query(int S, int X[], int T, int Y[]) {
    queue<pii> q;

    for(int i = 0; i < S; ++i) {
        cur[X[i]] = 1;
        q.emplace(X[i], 0);
        vtn.emplace_back(X[i]);
    }
    for(int i = 0; i < T; ++i) {
        cur[Y[i]] = 2;
        vtn.emplace_back(Y[i]);
    }

    sort(all(vtn), [&](int u, int v) {
        return tin[u] < tin[v];
    });

    for(int i = 0; i < S + T - 1; ++i) {
        vtn.emplace_back(LCA(vtn[i], vtn[i + 1]));
    }

    sort(all(vtn), [&](int u, int v) {
        return tin[u] < tin[v];
    });
    vtn.erase(unique(all(vtn)), vtn.end());

    auto add_vt = [&](int u, int v, int w) {
        vt[u].emplace_back(v, w);
        vt[v].emplace_back(u, w);
    };

    stack<int> s;
    for(int i = 0; i < isz(vtn); ++i) {
        while(not s.empty() && not is_ancestor(s.top(), vtn[i])) s.pop();
        if(s.empty()) s.emplace(vtn[i]);
        else {
            add_vt(s.top(), vtn[i], dis[vtn[i]] - dis[s.top()]);
            s.emplace(vtn[i]);
        }
    }

    ll res = oo;

    auto dfs = [&](auto self, int v, int p) -> vll {
        vll cur_dis(2, oo);
        if(cur[v]) cur_dis[cur[v] - 1] = 0;
        //vt, G
        for(auto &[u, w] : vt[v]) {
            if(u == p) continue;
            //cout<<u<<' '<<v<<' '<<w<<' '<<dis[u]<<' '<<dis[v]<<'\n';
            vll tmp = self(self, u, v);
            for(int i = 0; i < 2; ++i)
                cur_dis[i] = min(cur_dis[i], tmp[i] + w);
        }
        res = min(res, accumulate(all(cur_dis), 0LL));
        return cur_dis;
    };

    dfs(dfs, vtn[0], 0);
    for (auto x:vtn){
        cur[x] = 0;
        vt[x].clear();
    }
    /*for(int i = 0; i < S; ++i) {
        cur[X[i]] = 0;
        vt[X[i]].clear();
    }
    for(int i = 0; i < T; ++i) {
        cur[Y[i]] = 0;
        vt[Y[i]].clear();
    }
    vtn.clear();*/

    return res;
}

Subtask #1
15.0 / 15.0

# 결과 실행 시간 메모리 Grader output
1 Correct 36 ms 45656 KB Output is correct
2 Correct 4041 ms 56772 KB Output is correct
3 Correct 3681 ms 56772 KB Output is correct
4 Correct 3872 ms 56828 KB Output is correct
5 Correct 4097 ms 57436 KB Output is correct
6 Correct 3500 ms 56820 KB Output is correct
7 Correct 3661 ms 56656 KB Output is correct
8 Correct 3812 ms 57032 KB Output is correct
9 Correct 4086 ms 57592 KB Output is correct
10 Correct 3528 ms 56824 KB Output is correct
11 Correct 3696 ms 56780 KB Output is correct

Subtask #2
0 / 18.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 26 ms 45656 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #3
0 / 67.0

# 결과 실행 시간 메모리 Grader output
1 Correct 36 ms 45656 KB Output is correct
2 Correct 4041 ms 56772 KB Output is correct
3 Correct 3681 ms 56772 KB Output is correct
4 Correct 3872 ms 56828 KB Output is correct
5 Correct 4097 ms 57436 KB Output is correct
6 Correct 3500 ms 56820 KB Output is correct
7 Correct 3661 ms 56656 KB Output is correct
8 Correct 3812 ms 57032 KB Output is correct
9 Correct 4086 ms 57592 KB Output is correct
10 Correct 3528 ms 56824 KB Output is correct
11 Correct 3696 ms 56780 KB Output is correct
12 Incorrect 26 ms 45656 KB Output isn't correct
13 Halted 0 ms 0 KB -