제출 #843401

#제출 시각아이디문제언어결과실행 시간메모리
843401SortingSoccer Stadium (IOI23_soccer)C++17
8 / 100
3 ms1116 KiB
#include "soccer.h"
#include <bits/stdc++.h>

using namespace std;

const int N = 7 + 3;

bool f[N][N];
int prefix[N][N];
int n;

pair<int, bool> dp[N][N][N][N][N][2];

void init_prefix(){
    for(int i = 1; i <= n; ++i){
        for(int j = 1; j <= n; ++j){
            prefix[i][j] = !f[i - 1][j - 1];
        }
    }

    for(int i = 1; i <= n; ++i){
        for(int j = 1; j <= n; ++j){
            prefix[i][j] += prefix[i - 1][j] + prefix[i][j - 1] - prefix[i - 1][j - 1];
        }
    }
}

int get_sum(int x1, int y1, int x2, int y2){
    if(x1 > x2 || y1 > y2)
        return 0;
    return prefix[x2 + 1][y2 + 1] - prefix[x1][y2 + 1] - prefix[x2 + 1][y1] + prefix[x1][y1];
}

bool bad(int l1, int r1, int l2, int r2){
    if(l1 <= l2 && r2 <= r1)
        return false;
    if(l2 <= l1 && r1 <= r2)
        return false;
    return true;
}

int solve(int l1, int r1, int l2, int r2, int i, bool up){
    if(i == n)
        return 0;

    auto &[ans, solved] = dp[l1][r1][l2][r2][i][up];
    if(solved)
        return ans;

    solved = true;
    ans = 0;

    for(int l3 = 0; l3 < n; ++l3){
        for(int r3 = l3; r3 < n; ++r3){
            if(f[i][r3])
                break;

            if(bad(l1, r1, l3, r3))
                continue;
            if(bad(l2, r2, l3, r3))
                continue;

            if(!up && (l3 < l2 || r2 < r3))
                continue;

            bool new_up = up;
            if(up && (l2 < l3 || r3 < r2))
                new_up = false;

            int cand = r3 - l3 + 1;
            cand += solve(l1, r1, l3, r3, i + 1, new_up);
            ans = max(ans, cand);
        }
    }

    return ans;
}

int biggest_stadium(int _N, std::vector<std::vector<int>> F){
    n = _N;
    for(int i = 0; i < n; ++i)
        for(int j = 0; j < n; ++j)
            f[i][j] = F[i][j];

    init_prefix();

    int ans = 0;
    for(int i = 0; i < n; ++i){
        for(int l = 0; l < n; ++l){
            for(int r = l; r < n; ++r){
                if(f[i][r])
                    break;
                ans = max(ans, solve(l, r, l, r, i + 1, true) + r - l + 1);
            }
        }
    }

    return ans;
}
/*
3
1 0 0
0 0 0
0 0 0
*/
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